带有AVRO模式更新的问题

时间:2018-07-09 09:02:51

标签: apache-kafka avro akka-stream akka-kafka avro4s

我有一个简单的案例类:

  case class User(id: String, login: String, key: String)

我要添加字段“名称”

  case class User(id: String, login: String, name: String, key: String)

然后将其添加到Avro模式(user.avsc)

{
  "namespace": "test",
  "type": "record",
  "name": "User",
  "fields": [
    { "name": "id", "type": "string" },
    { "name": "login", "type": "string" },
    { "name": "name", "type": "string" },
    { "name": "key", "type": "string" }
  ]
}

该类用于其他案例类:

case class AuthRequest(user: User, session: String)

chema(auth_request.avsc)

{
  "namespace": "test",
  "type": "record",
  "name": "AuthRequest",
  "fields": [
    { "name": "user", "type": "User" },
    { "name": "session", "type": "string" }
  ]
}

在更改之后,我的消费者开始抛出异常

Consumer.committableSource(consumerSettings, Subscriptions.topics("token_service_auth_request"))
    .map { msg =>
      Try {
        val in: ByteArrayInputStream = new ByteArrayInputStream(msg.record.value())
        val input: AvroBinaryInputStream[AuthRequest] = AvroInputStream.binary[AuthRequest](in)
        val result: AuthRequest = input.iterator.toSeq.head !!!! here is exception
        msg.committableOffset.commitScaladsl()

        (msg.record.value(), result, msg.record.key())
      } match {
        case Success((a: Array[Byte], value: AuthRequest, key: String)) =>
          log.info(s"listener got $msg -> $a -> $value")

          context.parent ! value

        case Failure(e) => e.printStackTrace()
      }
    }
    .runWith(Sink.ignore)
  

java.util.NoSuchElementException:空流头位于   scala.collection.immutable.Stream $ Empty $ .head(Stream.scala:1104)在   scala.collection.immutable.Stream $ Empty $ .head(Stream.scala:1102)在   test.consumers.AuthRequestListener。$ anonfun $ new $ 2(AuthRequestListener.scala:39)     在scala.util.Try $ .apply(Try.scala:209)在   test.consumers.AuthRequestListener。$ anonfun $ new $ 1(AuthRequestListener.scala:36)     在   test.consumers.AuthRequestListener。$ anonfun $ new $ 1 $ adapted(AuthRequestListener.scala:35)     在akka.stream.impl.fusing.Map $$ anon $ 9.onPush(Ops.scala:51)在   akka.stream.impl.fusing.GraphInterpreter.processPush(GraphInterpreter.scala:519)     在   akka.stream.impl.fusing.GraphInterpreter.processEvent(GraphInterpreter.scala:482)     在   akka.stream.impl.fusing.GraphInterpreter.execute(GraphInterpreter.scala:378)     在   akka.stream.impl.fusing.GraphInterpreterShell.runBatch(ActorGraphInterpreter.scala:588)     在   akka.stream.impl.fusing.GraphInterpreterShell $ AsyncInput.execute(ActorGraphInterpreter.scala:472)     在   akka.stream.impl.fusing.GraphInterpreterShell.processEvent(ActorGraphInterpreter.scala:563)     在   akka.stream.impl.fusing.ActorGraphInterpreter.akka $ stream $ impl $ fusing $ ActorGraphInterpreter $$ processEvent(ActorGraphInterpreter.scala:745)     在   akka.stream.impl.fusing.ActorGraphInterpreter $$ anonfun $ receive $ 1.applyOrElse(ActorGraphInterpreter.scala:760)     在akka.actor.Actor.aroundReceive(Actor.scala:517)在   akka.actor.Actor.aroundReceive $(Actor.scala:515)在   akka.stream.impl.fusing.ActorGraphInterpreter.aroundReceive(ActorGraphInterpreter.scala:670)     在akka.actor.ActorCell.receiveMessage(ActorCell.scala:588)在   akka.actor.ActorCell.invoke(ActorCell.scala:557)在   akka.dispatch.Mailbox.processMailbox(Mailbox.scala:258)位于   akka.dispatch.Mailbox.run(Mailbox.scala:225)在   akka.dispatch.Mailbox.exec(Mailbox.scala:235)在   akka.dispatch.forkjoin.ForkJoinTask.doExec(ForkJoinTask.java:260)在   akka.dispatch.forkjoin.ForkJoinPool $ WorkQueue.runTask(ForkJoinPool.java:1339)     在   akka.dispatch.forkjoin.ForkJoinPool.runWorker(ForkJoinPool.java:1979)     在   akka.dispatch.forkjoin.ForkJoinWorkerThread.run(ForkJoinWorkerThread.java:107)

我试图清理内部版本并使缓存无效-我似乎在某种程度上缓存了先前版本的架构 请帮忙!

1 个答案:

答案 0 :(得分:1)

您需要使您的更改向后兼容,以使新字段可以为空并为其添加默认值。

{
  "namespace": "test",
  "type": "record",
  "name": "User",
  "fields": [
    { "name": "id", "type": "string" },
    { "name": "login", "type": "string" },
    { "name": "name", "type": ["null", "string"], "default": null },
    { "name": "key", "type": "string" }
  ]
}