Question

使用以下代码，如何在数据库中添加默认值“ user”和“ id”字段的用户名，例如对于第15个用户，该用户名变为“ user15”？

我不确定要在何处添加默认用户名，语法也不是100％。

说明：我想要一个静态字符串（“用户”），并将其与数据库中自动递增的“ id”字段连接起来。

更新：似乎不可能立即连接自动递增的值，因此：关于如何生成默认用户名的任何建议？用户名字段为UNIQUE。

for attribute in resp[0]['attributes']:
    if attribute['name'] == 'buttonState' and attribute['value']['data'] is False:
        # Do your thing here

Answer 1

我在评论中提出了这个建议，但让我尝试一个答案以使其更加充实。基本上，想法是插入新记录，然后获取插入ID，然后更新有问题的记录。

if (something_supposed_to_happen_here()) {
    $firstname = $profile['first_name'];
    $lastname = $profile['last_name'];
    $email = $profile['email'];
    $picture = $profile['picture']['url'];

    try {
        $conn = new PDO("mysql:host=$host;dbname=$dbname", $user, $pass);

        $conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
        $stmt = $conn->prepare("
            INSERT INTO users (
                firstname, 
                lastname, 
                email, 
                picture, 
                token
            ) 
            VALUES (
                :firstname, 
                :lastname, 
                :email, 
                :picture, 
                :token)"
            );
        $stmt->bindParam(':firstname', $firstname);
        $stmt->bindParam(':lastname', $lastname);
        $stmt->bindParam(':email', $email);
        $stmt->bindParam(':picture', $picture);
        $stmt->bindParam(':token', $accessToken);

        $stmt->execute();

        // Suggestion follows
        $insertId = $conn->lastInsertId();
        $stmt = $conn->prepare('UPDATE users SET username = :username WHERE id = :id');
        $userId = 'user' . $insertId;
        $stmt->bindParam(':username', $userId);
        $stmt->bindParam(':id', $insertId);
        $stmt->execute();
        // End suggestion

        echo "Thank you for registering";
    }
    catch(PDOException $e)
    {
        echo "Error: " . $e->getMessage();
    }
    $conn = null;

} else {

    $loginUrl = $helper->getLoginUrl('mywebsite.com/fblogin/index.php', $permissions);
    echo '<a href="' . $loginUrl . '">Log in with Facebook!</a>';
}

请注意，这假设您的自动递增ID字段称为id，而用户名字段称为username。

Answer 2

仅通过与Facebook的用户ID串联即可解决：

$firstname = $profile['first_name'];
$lastname = $profile['last_name'];
$email = $profile['email'];
$picture = $profile['picture']['url'];
$userstatus = "1";
$fbuserid = $profile['id'];
$defaultUsername = 'user_' . $fbuserid; // This line solved it. 

//<editor-fold desc="> Insert the data above this into the database">
try {
    $conn = new PDO("mysql:host=$host;dbname=$dbname", $user, $pass);

    $conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
    $stmt = $conn->prepare("INSERT INTO users (firstname, lastname, email, picture, status, token, oauth_uid) 
VALUES (:firstname, :lastname, :email, :picture, :userstatus, :token, :oauth_uid)");
    $stmt->bindParam(':firstname', $firstname);
    $stmt->bindParam(':lastname', $lastname);
    $stmt->bindParam(':email', $email);
    $stmt->bindParam(':picture', $picture);
    $stmt->bindParam(':userstatus', $userstatus);
    $stmt->bindParam(':token', $fbuserid); // just oauth_uid stored in a better named column, also storing that with the line below
    $stmt->bindParam(':oauth_uid', $fbuserid); // this is the original of this and the one above

设置默认用户名并连接ID

2 个答案: