将1个表连接到同一列的2个表

时间:2018-07-17 16:13:06

标签: sql sql-server

我有下表:

表1

+------+-----------+----------+
| Item | ProcessID | PersonID |
+------+-----------+----------+
| 111  |    33     |  1234567 |

表2

+------+----+------------+
| Item | ID | DelegateID |
+------+----+------------+
| 111  | 1  |  4567894   |

人员

+----------+------+
| PersonID | Name |
+----------+------+
| 1234567  | Jhon |
+----------+------+
| 4567894  | Larry|

我想这样加入他们

+-----------+--------+----------+
| ProcessID | Person | Delegate |
+-----------+--------+----------+
|    33     |  Jhon  |  Larry   |

但是仅仅做一个简单的连接并不能使我到达那里。

3 个答案:

答案 0 :(得分:1)

SELECT Table1.processid, Persons.name,  
 (select name from Persons where personid =Table2.delegatepersonid) as delegate
FROM Persons 
INNER JOIN Table1 ON Persons.personid = Table1.personid
INNER JOINTable2 ON Table1.item= Table2.item

答案 1 :(得分:0)

我认为这需要人员表的别名,因此可以在两个联接中使用它:personid和委托人id:

select P.*, T1.*, T2.*
from persons P
inner join table_1 T1 on P.personid = T1.personid 
inner join table_2 T2 on T1.item = T2.item
inner join persons P_del on T2.delegatepersonid = P_del.personid ;

答案 2 :(得分:0)

由于您要查找两个不同的Personid值,因此必须两次加入Persons

SELECT 
        one.processid
    ,   pone.name
    ,   ptwo.name
FROM table1 AS one 
INNER JOIN table2 AS two 
    ON one.item = two.item
INNER JOIN persons as pone
    ON pone.personid = one.personid
INNER JOIN persons as ptwo 
    ON ptwo.personid = two.delegatepersonid

我相信周星驰的解决方案也可能有效。