Question

我有一个简单的查询，例如：

SELECT
    1 AS [Result],
    'success' AS [ResultText]

IF (@TaskStatusName = 'COMPLETED')
    SELECT 
        5 AS [ToNotifiedResult],
        SELECT @TechniciansEmail = COALESCE(@TechniciansEmail + ';', '') + [Username]  
        FROM Employee  AS [E]
  INNER JOIN TaskNotification AS [TN] ON TN.EmpKey = E.EmpKey AND TaskId = '64BB7072-62A5-4C8E-A385-3B3DCB8BD1CA' AS [ToNotified]

问题在最后一次选择就说了

“选择”附近的语法不正确

“选择”字样标记为红色

我尝试将带括号的选择分组为：

 ,(SELECT @TechniciansEmail = COALESCE(@TechniciansEmail + ';', '') + [Username]  FROM Employee  AS [E]
  INNER JOIN TaskNotification AS [TN] ON TN.EmpKey = E.EmpKey AND TaskId = '64BB7072-62A5-4C8E-A385-3B3DCB8BD1CA' AS [ToNotified])

但是现在@ TechniciansEmail变量被标记为红色，我得到了

@TechniciansEmail附近的语法不正确。期待'（'或SELECT

我真的不知道我在做什么错，有什么想法吗？

Answer 1

此行：

SELECT @TechniciansEmail = COALESCE(@TechniciansEmail + ';', '') + [Username]

要么完全不合适，要么尝试创建一个子查询，在这种情况下，它需要放在括号中并具有自己的FROM子句。

实际上，根据问题的后半部分，您似乎应该将此行作为其自己的单独查询，因为它填充了一个变量：

SELECT  
    @TechniciansEmail = COALESCE(@TechniciansEmail + ';', '') + [Username]  
FROM 
    Employee  AS [E]
INNER JOIN 
    TaskNotification AS [TN] ON TN.EmpKey = E.EmpKey AND TaskId = '64BB7072-62A5-4C8E-A385-3B3DCB8BD1CA'

Answer 2

如果在存储过程中，则必须以条件开始。像这样如果@sastro = value 开始从参数=处选择* 结束其他开始

选择....... 结束

SQL Server：语法错误进入存储过程

2 个答案: