Question

我正在尝试获取商店订购的所有可用产品的总列表以及用户加入商店的时间，以便首先列出最近加入商店的用户，然后依此类推。请注意，无论该用户是否属于该商店，都需要显示所有产品（这些产品将在最后显示，并且优先级最低）。

Class User
  has_many :memberships
  has_many :stores, through: :memberships

  has_many :active_memberships, -> {active}, class_name: "Membership"
  has_many :active_stores, through: :active_memberships
end

Class Store
  has_many :memberships
  has_many :users, through: :memberships

  has_many :active_memberships, -> {active}, class_name: "Membership"
  has_many :active_users, through: :active_memberships

  has_and_belongs_to_many :products,  association_foreign_key: :product_id
end

Class Membership
  belongs_to :users
  belongs_to :stores

  scope :active, -> {where(active: true).order(:created_at)}
end

Class Product
  has_and_belongs_to_many :stores,
    join_table:           :product_stores,
    foreign_key:          :product_id
end

这是我到目前为止所要做的。

user = User.find(1)
ids = user.active_stores.ids
subscribed_store_products = Product.joins(stores: :memberships).where("stores.id = Any({#{ids}) AND memberships.user_id = 1").order("memberships.created_at")

non_susbscribed_store_products = Product.joins(:stores).where("stores.id != Any({#{ids})")

然后将两者合并以接收列表。我想知道是否可能缺少一些东西。

基于2个单独的联接表进行订购

0 个答案: