Question

有人可以告诉我为什么当我编译它时，C告诉我总和不能表示为int吗？我不知道如何调试这一。我认为我创建的结构很好，而且计数和功能也不错。因此，请帮助我找出代码中的错误。

#include <stdio.h>
#include <stdlib.h>

struct node{
    int data;
    struct node *next;
};

struct node *my_list();
int sum_list_values(struct node *list);


int main(){
    struct node *list = my_list();
    int sum = sum_list_values(list);
    printf("%d", sum);

    return 0;
}


struct node *my_list(){
    struct node *new = malloc(sizeof(struct node));
    new->data = 1;

    struct node *new1 = malloc(sizeof(struct node));
    new->data = 3;

    struct node *new2 = malloc(sizeof(struct node));
    new->data = 3;

    struct node *new3 = malloc(sizeof(struct node));
    new->data = 7;

    new->next = new1;
    new1->next = new2;
    new2->next = new3;
    new3->next = NULL;


    return new;
}

int sum_list_values(struct node *list){
    struct node *current = list;
    int sum = 0;

    while(current != NULL){
        printf("Hello");
        sum = sum + current->data;//counter
        current = current->next;//increment
    }

    return sum;
}

Answer 1

您犯了一个不明显的小错误

代码部分

struct node *new1 = malloc(sizeof(struct node));
new->data = 3;

struct node *new2 = malloc(sizeof(struct node));
new->data = 3;

struct node *new3 = malloc(sizeof(struct node));
new->data = 7;

每次都将值分配给同一节点，新创建的节点将保留未分配的数据（不良节点）。

应改为

struct node *new1 = malloc(sizeof(struct node));
new1->data = 3;

struct node *new2 = malloc(sizeof(struct node));
new2->data = 3;

struct node *new3 = malloc(sizeof(struct node));
new3->data = 7;

希望这会有所帮助。

继续提问，保持成长：）

C中有符号整数溢出

1 个答案: