Question

如何转换此数组：

let strArr = ["10100", "10111", "11111", "01010"];

成二维数组。

二维数组将是：-

Answer 1

您可以从字符串和映射号中获得可迭代项。

var array = ["10100", "10111", "11111", "01010"],
    matrix = array.map(s => Array.from(s, Number));
    
console.log(matrix);

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Answer 2

如果结果需要是每个字符串的每个字符包含一个元素的数组数组，则可以在循环或映射中将每个字符串与空字符串分开。

let res = [];
let strArr = ["10100", "10111", "11111", "01010"];
strArr.map((str) => {
    res.push(str.split(''))
});
console.log(res);

Answer 3

遍历每个项目并将其内容分散到一个数组中-然后转换为数字。

let newArr = strArr.map(item => [...item].map(Number));

Answer 4

let inArr = ["10100", "10111", "11111", "01010"];
let outArr = inArr.map( line => line.split("").map(  item =>  +item  ) );

console.log(outArr);

let inArr = ["10100", "10111", "11111", "01010"];
let outArr = inArr.map( line => line.split("").map(  item =>  +item  ) );

Answer 5

这样，您将获得一个二维数组，其中包含零和一

const newArr = strArr.map((a) => a.split("").map(char => char === "0"? 0: 1))

Answer 6

let strArr = ["10100", "10111", "11111", "01010"];
let numColumns = strArr[0].length;
let numRows = strArr.length;
let string = strArr.join('');
let result = [];

for (let row = 0; row < numRows; row++) {
  result.push([]);
  for (let column = 0; column < numColumns; column++) {
    result[row].push(parseInt(string.charAt(row*5 + column), 10));
  }
}

console.log(result);

如何将字符串数组转换为二维数组？

6 个答案: