Question

单击CBV按钮时，我在UpdateView（Submit）内使用表单的代码不会保存到DB。我看不出有什么问题。

views.py

class BHA_UpdateView(UpdateView):
    template_name = 'bha_test.html'
    context_object_name = 'bha'
    model = BHA_List
    success_url = reverse_lazy('well_list')
    pk_url_kwarg = 'pk_alt'
    form_class = BHA_overall_Form

    def get_context_data(self, **kwargs):
        context = super().get_context_data(**kwargs)
        api = get_well_api(self.request)
        context['single_well_bha_list'] = BHA_List.objects.filter(well=api)
        return context

    def form_valid(self, form):
        self.object = form.save()
        return super().form_valid(form)

models.py

class WellInfo(models.Model):
    api = models.CharField(max_length=100, primary_key=True)
    well_name = models.CharField(max_length=100)
    status = models.CharField(max_length=100)

class BHA_List(models.Model):
    well = models.ForeignKey(WellInfo, 'CASCADE', related_name='bha_list')
    bha_number = models.CharField(max_length=100)

class BHA_overall(models.Model):
    bha_number = models.ForeignKey(BHA_List, 'CASCADE', related_name='bha_overall')
    drill_str_name = models.CharField(max_length=111)
    depth_in = models.CharField(max_length=111)

bha_test.html

<form method="POST">
  {% csrf_token %}
  {{ form.as_p }}
  <input type="submit" class='btn btn-primary' value="Submit">
</form>

forms.py

from django import forms
from contextual.models import BHA_overall

class BHA_overall_Form(forms.ModelForm):
    class Meta():
        model = BHA_overall
        fields = '__all__'

因此有一个model = BHA_List，并且还有另一种通过外键与模型相关的形式。表单字段将显示给用户，并且在单击“提交”按钮后，应将用户输入保存到DB，但不会。怎么了？

Answer 1

您的ModelForm模型与您的UpdateView模型不匹配

您要使用以下方式声明您的ModelForm：

model = BHA_Overall

您的UpdateView具有：

model = BHA_List

请记住，UpdateViews使用model =执行查询集，因此它们可以将Model实例分配给ModelForm，因为它们是不同的模型，因此很可能不匹配。

此外，如果您不进行额外的验证或修改ModelForm.instance，则无需在UpdateView中覆盖form_valid方法。

Django-UpdateView表单无法保存

1 个答案: