Question

有此查询

"SELECT DISTINCT ID, DATE FROM MAIN_TAB ORDER BY ID ASC"

如何在每行的前面打印ID字段的不同组合的总数，例如TOTAL_DISTINCT_VALUES：

ID    DATE       TOTAL_DISTINCT_VALUES
37870 02/07/2018                     3
37870 03/07/2018                     3
37870 04/07/2018                     3
55887 04/07/2018                     2
55887 03/07/2018                     2
61891 02/07/2018                     1
44891 02/07/2018                     1
75891 02/07/2018                     1

Answer 1

您可以使用count和group by

SELECT ID, DATE, count(*) TOTAL_DISINCT_VALUE
FROM MAIN_TAB 
GROUP BY ID, DATE
ORDER BY ID ASC

但是向您看数据样本似乎只需要将id续，因此您可以对id为的计数组使用联接

select t.id, a.date, t.TOTAL_DISTINCT_VALUE
from  MAIN_TAB a
inner JOIN (
    select id, count(*) TOTAL_DISTINCT_VALUE 
    FROM MAIN_TAB 
    group by ID 
) t on a.id = t.id

或barmar建议。计数（不明确的日期）

select t.id, a.date, t.TOTAL_DISTINCT_VALUE
from  MAIN_TAB a
inner JOIN (
    select id, count(distinct date) TOTAL_DISTINCT_VALUE 
    FROM MAIN_TAB 
    group by ID 
) t on a.id = t.id

Answer 2

使用group by子句

  SELECT ID, DATE,count(*) as distinct_value FROM MAIN_TAB 
    group by ID, DATE
    ORDER BY ID ASC

Answer 3

尝试一下：

select ID,DATE,count(*) as TOTAL_DISINCT_VALUE from MAIN_TAB group by ID,DATE order by ID asc;

，并将*替换为ID和DATE以外的任何其他列名称。

不同的2个不同的列，如何在每一行中打印总组合

3 个答案: