Angular 5:表格内的动态表单验证

时间:2018-07-30 17:13:12

标签: angular angular5 angular-forms angular-formbuilder

我正在尝试使用表单组验证表内的输入字段,但无法实现相同目的。 我使用* ngFor来迭代数据,因为我必须在表的第一列中显示该数据,而其他列只是输入文本字段,必须在其中添加表单验证。 因此,我为该字段的唯一表单控件名称添加了索引。

HTML代码

<form [formGroup]="tableForm">
    <table class="shop-table table-responsive" cellspacing="0">
       <tbody>
         <tr class="cart_item" *ngFor="let data of final_selected_data; let i= index;">
           <td class="product-thumbnail">
             <a href="#"><img src="assets/images/nike.jpg" alt="" width="100"></a>
           </td>
           <td class="product-name">
              <a href="#">{{data.size_ui}} ({{data.color_ui}}, {{data.material_ui}})</a> </td>
            <td class="product-quantity" data-title="SKU">
               <div class="quantity buttons_added">
                  <input step="1" value="" title="SKU" class="text" size="6" type="text" placeholder="SKU*" style="width:80px;" matInput [formControl]="tableForm.controls['variant_sku'+i]">
                </div>
            </td>
            <td class="product-quantity" data-title="Price">
               <div class="quantity buttons_added">
                  <input step="1" min="0" max="" value="" title="Price" class="text" size="6" type="number" placeholder="Price*" style="width:80px;" matInput [formControl]="tableForm.controls['variant_price'+i]">
                </div>
             </td>
               <td class="product-remove">
                  <a href="#" class="remove" title="Remove this item"><mat-icon>delete</mat-icon></a> 
               </td>
             </tr>
            </tbody>
           </table>
          </form>

Component.ts

ngOnInit() {
   for(let i = 0; i < this.final_selected_data.length; i++){
          var j = (i).toString();
          let variant_sku = 'variant_sku'+j;
          let variant_price = 'variant_price'+j;
          let variant_stock = 'variant_stock'+j;
          let variant_moq = 'variant_moq'+j;
          this.tableForm = this.fb.group({
            variant_sku: [null, Validators.compose([Validators.required])],
            variant_price: [null, Validators.compose([Validators.required])]
          });
       }
}

错误

  

错误错误:找不到具有未指定名称属性的控件

1 个答案:

答案 0 :(得分:2)

您现在要做的是,无论数组的长度如何,都只能在窗体内部创建2个窗体控件。您需要的是一个this.tableForm = this.fb.group({ arr: this.fb.array([]) }) let arr = this.tableForm.get('arr') as FormArray; for (let i = 0; i < this.final_selected_data.length; i++) { arr.push(this.fb.group({ variant_sku: [this.final_selected_data[i].variant_sku, [Validators.required]] })) } ,您可以将数组中每个对象的新表单组推送到其中。因此,缩短的版本应为:

<form [formGroup]="tableForm">
  <table>
    <tbody formArrayName="arr">
      <tr *ngFor="let a of this.tableForm.get('arr')['controls']; let i= index;">
        <td class="product-quantity" [formGroupName]="i">
          <input formControlName="variant_sku">
          <!-- not pretty, but just for demonstration! -->
          <p *ngIf="a.hasError('required', 'variant_sku')">Required!</p>
        </td>
      </tr>
    </tbody>
  </table>
</form>

然后在模板中迭代表单数组:

172.20.5.246

演示:https://stackblitz.com/edit/angular-vcjjfr?file=src%2Fapp%2Fapp.component.html

相关问题