获取内部服务器错误(500)-CodeIgniter

时间:2018-07-31 09:43:33

标签: javascript php ajax codeigniter codeigniter-3

在我的CodeIgniter项目中,我需要将数据插入db表中,

  

内部服务器错误(500)

发出使用Ajax将数据添加到数据库的命令。

我的Ajax代码在下面,

$("#rsvp_form").validate({
    rules: {
        uname: {
            required: true,
            minlength: 8
        },
        uemail: "required",
        umessage: {
            required: true,
            maxlength: 100
        }
    },
    messages: {
        uname: {
            required: "Please enter your name",
            minlength: jQuery.validator.format("At least 8 characters required!")
        },
        uemail: "Please enter your email",
        umessage: {
            maxlength: jQuery.validator.format("Please enter no more than 100 characters!")
        },
    },
    // ajax request
    submitHandler: function (form) {

        var formData = {
            'user_name': $('input[name=uname]').val(),
            'user_email': $('input[name=uemail]').val(),
            'user_wish': $('input[name=umessage]').val()
        };

        // loader
        $(".loader").show();

        // ajax request
        $.ajax({
            type: "POST",
            url: "<?php echo base_url(); ?>index.php/Welcome/create_wish",
            data: formData,
            dataType: "json",
            success: function (data) {

                // if send data successfull
                if (data.status === 'success') {

                    $(".loader").hide();
                    $(form).fadeOut("slow");
                    setTimeout(function () {
                        $(".form-success").show("slow");
                    }, 300);

                    // if send data something wrong 
                } else if (data.status === 'error') {

                    $(".loader").hide();
                    $(form).fadeOut("slow");
                    setTimeout(function () {
                        $(".form-error").show("slow");
                    }, 300);
                }

            }
        });
        return false;
    }

});

我的Welcome控制器功能如下:,

public function create_wish() {
    $this->load->model("model_wishes");
    $data = array(
    'user_name' => $this->input->post('uname'),
    'user_email' => $this->input->post('uemail'),
    'user_wish' => $this->input->post('umessage')
    );
    $this->model_wishes->createWish($data);
}

model_wishes模型在这里,

function createWish($data) {
    $this->db->insert("wishes", $data);
}

welcome_message视图是

<form id="rsvp_form" action="">
<div class="row">
    <div class="form-group col-md-6">
        <label for="post-name">Name</label>
        <input autocomplete='name' type="text" class="form-control" id="uname" name="uname" required />
    </div>
    <div class="form-group col-md-6">
        <label for="post-email">Email</label>
        <input autocomplete='email' type="email" class="form-control" id="uemail" name="uemail" required/>
    </div>
</div>
<div class="row">
    <div class="form-group col-md-12 margin-b-2">
        <label for="post-message">Message</label>
        <textarea class="form-control" id="umessage" rows="5" name="umessage"></textarea>
    </div>
</div>
<div class="row">
    <div class="form-group col-md-12 text-left mb-0">
        <button id="btn-create" type="submit" class="button-medium btn btn-default fill-btn">Post Wish</button>
    </div>
</div>

单击Post Wish按钮时,会得到XHR failed loading: POST和错误

POST http://localhost/CodeIgniterProj/index.php/Welcome/create_wish 500 (Internal Server Error)

请让我知道实际导致内部服务器错误的原因,以及如何解决此问题。

3 个答案:

答案 0 :(得分:3)

您使用了错误的帖子输入,请检查下面的更新代码

public function create_wish() {
    $this->load->model("model_wishes");
    $data = array(
    'user_name' => $this->input->post('user_name'),
    'user_email' => $this->input->post('user_email'),
    'user_wish' => $this->input->post('user_wish')
    );
    $this->model_wishes->createWish($data);
}

答案 1 :(得分:0)

使用 site_url

代替 base_url
site_url('Welcome/create_wish')

答案 2 :(得分:0)

希望这对您有帮助:

您的submitHandler代码应如下所示:

submitHandler: function (form) 
{
  var formData = $(form).serialize();
  $(".loader").show();
  console.log(formData);
  $.ajax({
    type: "POST",
    url: "<?=site_url('Welcome/create_wish'); ?>",
    data: formData,
    dataType: "json",
    success: function (data) {
      alert(data);
    }
  });
}

您的控制器create_wish应该是这样的:

public function create_wish() 
{
    $this->load->model("model_wishes");
    $user_name = $this->input->post('uname'));
    $user_email = $this->input->post('uemail');
    $user_wish = $this->input->post('umessage');

    $data = array(
      'user_name' => $user_name,
      'user_email' => $user_email,
      'user_wish' => $user_wish
    );
    $this->model_wishes->createWish($data);
    $response = array('status' => 'success');
    echo json_encode($response);
}