Question

我正在使用PHPMailer来构建联系表单，并且我正在寻找一个变量（$ msg）以显示成功或失败消息，这取决于最终用户是否正确填写了表单。如果正确填写了表单，则（$ msg）变量会成功执行回显，但是，如果用户未正确填写表单，则$（msg）变量将不会回显，而是收到一个致命错误，内容如下：

致命错误：未捕获PHPMailer \ PHPMailer \ Exception：无效地址：（Reply-To）：在/home/k4piavsj0bsc/public_html/phpmailer/src/PHPMailer.php:1004中堆栈跟踪：＃0 / home / k4piavsj0bsc / public_html /phpmailer/src/PHPMailer.php(973）：PHPMailer \ PHPMailer \ PHPMailer-> addOrEnqueueAnAddress（'Reply-To'，``，''）＃1 /home/k4piavsj0bsc/public_html/contactForm.php(18）：PHPMailer \ PHPMailer \ PHPMailer-> addReplyTo（''）＃2 /home/k4piavsj0bsc/public_html/contactForm.php(30）：sendemail（'info @ purplelime ...'，``，``，''）＃3 / home / k4piavsj0bsc / public_html / index.php（9）：include（'/ home / k4piavsj0 ...'）＃4 {main}在/home/k4piavsj0bsc/public_html/phpmailer/src/PHPMailer.php中抛出1004 < / p>

这是我的代码，如果最终用户未完成表单或从服务器端失败，没有人知道如何获取（$ msg）变量吗？

<?php

use PHPMailer\PHPMailer\PHPMailer;
use PHPMailer\PHPMailer\Exception;

$msg = "";

if (isset($_POST['submit'])) {
    require 'phpmailer/src/Exception.php';
    require 'phpmailer/src/PHPMailer.php';
    require 'phpmailer/src/SMTP.php';

    function sendemail ($to, $reply, $subject, $body) {
        $mail = new PHPMailer(true);
        $mail->setFrom('test@gmail.com', 'PLT Contact Form - Email');
        $mail->addAddress($to);
        $mail->addReplyTo($reply);
        $mail->Subject = $subject;
        $mail->Body = $body;
        $mail->IsHTML(false);

        return $mail->send();
    }

    $email = $_POST['email'];
    $subject = $_POST['subject'];
    $body = $_POST['body'];

    if (sendemail('info@test.com', $email, $subject, $body)) {
        $msg = 'Email has been sent, Thank you!';
    } else
        $msg = 'Email failed, please try again later';

  }

?>


<html>

<title>Contact Form Using PHPMailer</title>


<body>

    <div id="contactInnerWrapper">
        <a href="#"><span id="close">&times;</span></a>
        <h1 id="h1contactForm">Get in touch</h1>
            <form method="post" action="contactForm.php">
                <label for="email">Email address:</label><br>
                <input  type="email" name="email"  placeholder="Enter email" id="email">
                <label for="subject">Subject:</label>
                <input  type="text" name="subject" id="subject"><br>
                <label for="body">What would you like to ask us?</label><br>
                <textarea  type="text" name="body" rows="7" id="content"></textarea>
                <button type="submit" name="submit" id="submit" value="send">Submit</button>
            </form>
            <br><br>
            <?php echo $msg; ?>
    </div>

    <script type="text/javascript" src="general.js"></script>

 </body>

</html>

Answer 1

将最后一个if语句更改为此

$email = filter_var($email, FILTER_SANITIZE_EMAIL); // 
if (filter_var($email, FILTER_VALIDATE_EMAIL) && !empty($subject) && !empty($body)) {
    try {
        if (sendemail('info@purplelimetree.com', $email, $subject, $body))
            $msg = 'Email has been sent, Thank you!';
        else
            $msg = 'Error sending email';
    }catch(Excpetion $e) {
        $msg = 'Sending email failed, error: '.$e->getMessage();
    }
} else
    $msg = 'Email failed, incomplete/invalid data';

使用FILTER_SANITIZE_EMAIL删除电子邮件中的所有非法字符。
FILTER_VALIDATE_EMAIL过滤器将验证电子邮件地址。
检查身体和主题是否为空。
尝试发送电子邮件，如果出现致命错误，请正确捕获并返回说明性消息。
如果sendemail函数返回正确的设置成功消息，否则返回错误消息。

Answer 2

我认为以下代码将帮助您理解和解决问题。

$email = isset($_POST['email']) ? $_POST['email']:'';
$subject = isset($_POST['subject']) ? $_POST['subject']:'';
$body = isset($_POST['body']) ? $_POST['body']:'';

$is_valid_email = filter_var($email, FILTER_VALIDATE_EMAIL);

$status = false;
if ($email!='' && $is_valid_email==true && $subject!='' && $body!='') {
    $status = sendemail('info@purplelimetree.com', $email, $subject, $body)
}
if($status==true){
    $msg = 'Email has been sent, Thank you!';
} else
    $msg = 'Email failed, please try again later';
}

如果数据丢失，php不会回显错误消息-而是显示php致命错误

2 个答案: