Question

我试图计算一列中的非空行，但它计算所有行，并计算具有字符串“ 1”的列中的行。我能够为第一列计算具有字符串“ 1”的列中的行，但是在第二列中，它也计算为“ 0”。我在这里看到了一些文章，但未能解决问题。

SELECT NAME as Agent_Name, COUNT(case when Thumbs_Up= 1 then 1 else null end) as Thumbs_Up, 
   COUNT(case when No_Solution_Found =1 then 1 else null end) as No_Solution,
   COUNT(case when Save is null then 0 else 1 end) as Total_Saves,
 FROM table 
 GROUP BY NAME

表格：

Name      | Thumbs_up | No_Solution_Found | Save
Jonathan  | 1         | 0                 | Saved  
Mike      | 0         | 1                 | Null    
Peter     | 1         | 0                 | Null  
Mike      | 1         | 0                 | Saved
Peter     | 0         | 1                 | Saved
Mike      | 1         | 0                 | Saved
Peter     | 0         | 1                 | Saved

预期结果：

Name      | Thumbs_up | No_Solution       | Total_Save
Jonathan  | 1         | 0                 | 1
Mike      | 2         | 1                 | 2
Peter     | 1         | 2                 | 2

Answer 1

尝试使用SUM而不是COUNT

SELECT NAME as Agent_Name, 
   SUM(case when Thumbs_Up = 1 then 1 else 0 end) as Thumbs_Up, 
   SUM(case when No_Solution_Found =1 then 1 else 0 end) as No_Solution,
   SUM(case when Save is null then 0 else 1 end) as Total_Saves,
 FROM table 
 GROUP BY NAME

Answer 2

由于只有Save列具有NULL，因此我认为这是您遇到问题的列。

在查询中，您写道：

COUNT(case when Save is null then 0 else 1 end) as Total_Saves,

也就是说，您将NULL替换为0，这是一个非null值，因此会被计数。

您大概想写：

COUNT(Save) as Total_Saves

（顺便说一句，查询中as Total_Saves之后有一个逗号，该逗号不属于该逗号，因为后面没有其他列表达式。）

Answer 3

尝试以下查询-：

Select 
Name,
sum(Thumbs_up),
sum(No_Solution_Found),
count(case when [Save] is not null then 1 else null end) as Total_save 
from TABLE 
group by Name

SQL Server 2014

SQL-计算非NULL值，并计算具有字符串“ 1”的行

3 个答案: