Question

我正在使用Symfony 4，并且正在尝试从存储过程中获取结果，但是使用了学说却无法正常工作。如果我使用PDO，它会工作。为什么？!!!

这是我的教义代码：

$conn = $this->getDoctrine()->getManager()->getConnection();
$out = 1;            
$sql = 'EXEC SP_INSERT @IdTipoSuceso = ? , @Idprestador = 1 , @Descripcion = 1';

$stmt = $conn->prepare($sql);
$stmt->bindParam(1,$out, PDO::PARAM_INT|PDO::PARAM_INPUT_OUTPUT,4000);


$stmt->execute();
$result = $stmt->fetchAll();
$stmt->closeCursor();

doctrine.yaml

parameters:
    # Adds a fallback DATABASE_URL if the env var is not set.
    # This allows you to run cache:warmup even if your
    # environment variables are not available yet.
    # You should not need to change this value.
    env(DATABASE_URL): ''

doctrine:
    dbal:
        # configure these for your database server
        driver: 'sqlsrv'
        url: '%env(resolve:DATABASE_URL)%'
    orm:
        auto_generate_proxy_classes: '%kernel.debug%'
        naming_strategy: doctrine.orm.naming_strategy.underscore
        auto_mapping: true
        mappings:
            App:
                is_bundle: false
                type: annotation
                dir: '%kernel.project_dir%/src/Entity'
                prefix: 'App\Entity'
                alias: App

这是我使用pdo的代码，它可以正常工作：

$pdo = new PDO( 'sqlsrv:Server=127.0.0.1,1433;Database=db', 'user', 'pw');
        $query ='EXEC SP_INSERT @IdTipoSuceso = ? , @Idprestador = 1 , @Descripcion = 1';
        $stmt = $pdo->prepare($query);
        $out = 1;
        $stmt->bindParam(1, $out, PDO::PARAM_INT | \PDO::PARAM_INPUT_OUTPUT, 200);
        $stmt->execute();
        $result = $stmt->fetchAll();
        $stmt->closeCursor();

我需要在理论上做这件事。

Answer 1

您为什么要使用fetchAll？

只需使用类似的内容：

$query = 'exec INTAK_NOWY_KONTAKT @id_kontrahenta = ?, @nazwisko = ?, @imie = ?, @tel = ?, @e_mail = ?, @id_kontaktu = ?';

$params = array(
    $id_kontrahenta, $nazwisko, $imie, 
    $tel, $e_mail, $id_kontaktu
);

$types = array(
    SQLSRV_PARAM_IN, SQLSRV_PARAM_IN, SQLSRV_PARAM_IN, 
    SQLSRV_PARAM_IN, SQLSRV_PARAM_IN, SQLSRV_PARAM_OUT
);

$con = $this->entityManager->getConnection();

return $con->executeQuery($query, $params, $types);

Symfony 4学说sqlsrv如何从存储过程获取输出

1 个答案: