我一直在编写以下代码，以查找错误的值并将其替换为正确的值。
我在这里有两个文件，Source =分隔的文本文件，如下所示。
J48309A0580113A27E053A2DEF40AC8B8,Z9e578475,
7e241974c714459997e20fe6e195ffb1,BD17946 and BD38168,
和我的目标xmlJRN文件如下所示。 （多个xmlJRN文件）
<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<!DOCTYPE eGAD SYSTEM "eGAD.Dtd">
<eGAD pakUID="PID_77F0F469AFE61B4A8121AA84EB349B6C">
<document docID="1" docMasterID="1A5D331DDF8A84385F77B621C3F9CD86" docInstanceID="49E3D61E9CE1DF43BDD042F296913C88">
<VendorId>7618CEADE31441C99FE1BC07E325E0FA</VendorId>
<DocTypeId>CE3CD095580647389ED402675B43BE16</DocTypeId>
<AccNo>TXT:</AccNo>
<StmtDate>20161128</StmtDate>
<DDSDocValue name="UniqueDocID" type="text" len="32">J48309A0580113A27E053A2DEF40AC8B8</DDSDocValue>
<NumberOfPages value="8"/>
<Skipped>
<SPages></SPages>
</Skipped>
</document>
<document docID="1" docMasterID="1A5D331DDF8A84385F77B621C3F9CD86" docInstanceID="49E3D61E9CE1DF43BDD042F296913C88">
<VendorId>7618CEADE31441C99FE1BC07E325E0FA</VendorId>
<DocTypeId>CE3CD095580647389ED402675B43BE16</DocTypeId>
<AccNo>TXT:1</AccNo>
<StmtDate>20161128</StmtDate>
<DDSDocValue name="UniqueDocID" type="text" len="32">P48309A0580113A27E053A2DEF40AC8B8</DDSDocValue>
<NumberOfPages value="8"/>
<Skipped>
<SPages></SPages>
</Skipped>
</document>
</eGAD>
我想做的是，我从文本文件中读取了第一个GUID，并将其与每个JRNxml的文档组进行比较，如果找到匹配的方式，我将用文本文件的第二个值替换innertext值。
下面是我的代码
static void Main()
{
//Load the File
using (StreamReader reader = new StreamReader("C:\\temp1\\AllXMLData_FinalOutput.txt"))
{
string line = reader.ReadLine();
string[] value = new string[0];
while ((line = reader.ReadLine()) != null)
{
// Load the file and read the GUID and Plan number one by one From Source Text file
var values = line.Split(',');
string GUIDfromTxt = values[0]; // Holds the GUID value from the Source Txt file
string PlanNofromTxt = values[1]; // Holds the Plan number valuse from the Source Txt file
// Read the XML's one by one from Destination folder and search for the GUID on each group
string folderPath = "C:\\Temp2";
DirectoryInfo di = new DirectoryInfo(folderPath);
FileInfo[] rgFiles = di.GetFiles("*.JRN");
foreach (FileInfo fi in rgFiles)
{
XmlDocument xmljrndoc = new XmlDocument();
XmlNodeList xmlnode;
FileStream fs = new FileStream(fi.FullName, FileMode.Open, FileAccess.ReadWrite); // Open file
xmljrndoc.Load(fs);
xmlnode = xmljrndoc.GetElementsByTagName("document");
string JRNGUID = "";
string JRNPLAN = "";
for (int k = 0; k < xmlnode.Count; k++) // Read all the elements one by one
{
JRNGUID= xmlnode[k].SelectSingleNode("DDSDocValue[@name='UniqueDocID']").InnerText.Trim(); //get guid value from Destination XML
JRNPLAN= xmlnode[k].SelectSingleNode("AccNo").InnerText.Trim(); //get Plan number value from Destination XML
Console.WriteLine("Value From Text File GUID : " + GUIDfromTxt + " Plan Number : " + PlanNofromTxt);
Console.WriteLine("Value From JRN File GUID : " + JRNGUID + " Plan Number : " + JRNPLAN);
if ((GUIDfromTxt == JRNGUID) && (JRNPLAN.Length <= 8)) // check the GUID matches
{
Console.WriteLine("OLD Value : "+ JRNPLAN + " NEW Value : " + PlanNofromTxt); xmlnode[k].SelectSingleNode("AccNo").InnerText.Replace(JRNPLAN, PlanNofromTxt); // replace the txt plan to xml plan tag
}
Console.WriteLine("Xml JRN Value after find and replace " + JRNGUID + " " + JRNPLAN);
}
fs.Close();
//fs.Dispose();
}
Console.ReadKey();
}
//reader.Close();
//reader.Dispose();
}
}
此代码在最后一部分中不起作用，无法替换xmlJRN文件中的文本。
有人可以帮助我找到我在这里犯的错误吗？非常感谢您的帮助。我想替换一个值并保存文件。
EDIT1： 感谢您的建议，我已经完成了代码。这是最后一个。
static void Main()
{
StreamWriter sw = new StreamWriter("C:\\Temp3\\Log.txt", false, Encoding.ASCII); // log file declaration
string folderPath = "C:\\Temp2";
DirectoryInfo di = new DirectoryInfo(folderPath);
FileInfo[] rgFiles = di.GetFiles("*.JRN");
foreach (FileInfo fi in rgFiles)
{
sw.WriteLine("Opening XML JRN File : " + fi.Name);
XmlDocument xmljrndoc = new XmlDocument();
XmlNodeList xmlnode;
FileStream fs = new FileStream(fi.FullName, FileMode.Open, FileAccess.ReadWrite);
xmljrndoc.Load(fs);
xmlnode = xmljrndoc.GetElementsByTagName("document");
string JRNGUID = "";
string JRNPLAN = "";
for (int k = 0; k < xmlnode.Count; k++) // Read all the elements one by one
{
JRNGUID = xmlnode[k].SelectSingleNode("DDSDocValue[@name='UniqueDocID']").InnerText.Trim(); //get guid value from Destination XML
JRNPLAN = xmlnode[k].SelectSingleNode("AccNo").InnerText.Trim();
sw.WriteLine("FROM XMLJRN file - GUID : " + JRNGUID + " PlanNumber : " + JRNPLAN);
StreamReader reader = new StreamReader("C:\\temp1\\AllXMLData_FinalOutput.txt");
sw.WriteLine("Reading Txt file for GUID Search... ");
string line = reader.ReadLine();
string[] value = new string[0];
while ((line = reader.ReadLine()) != null)
{
// Load the file and read the GUID and Plan number one by one
var values = line.Split(',');
string GUIDfromTxt = values[0]; // Holds the GUID value from the Txt file
string PlanNofromTxt = "Compass:" + values[1]; // Holds the Plan number valuse from the Txt file
sw.WriteLine("FROM text file - GUID : " + GUIDfromTxt + " PlanNumber : " + PlanNofromTxt);
if ((GUIDfromTxt == JRNGUID) && (JRNPLAN.Length <= 8)) // check the GUID matches
{
sw.WriteLine("GUID MATCH FOUND!");
sw.WriteLine("OLD Value : " + JRNPLAN + " replaced with NEW Value : " + PlanNofromTxt);
fs.Close();
FileStream fs1 = new FileStream(fi.FullName, FileMode.Append, FileAccess.Write);
xmljrndoc.Save(@"C:\\Temp3\\" + fi.Name); // replace the txt plan to xml plan tag
fs1.Close();
// xmljrndoc.Save(fi.FullName);
}
else
{
sw.WriteLine("GUID MATCH NOT FOUND!");
}
}
}
}
sw.Close();
}
答案 0 :(得分：0)
String.Replace实际上并不直接修改字符串。它返回带有副本的字符串的副本。您仍然需要自己将修改后的值分配给InnerText。
例如，代替：
xmlnode[k].SelectSingleNode("AccNo").InnerText.Replace(JRNPLAN, PlanNofromTxt);
您需要执行以下操作：
var node = xmlnode[k].SelectSingleNode("AccNo");
node.InnerText = node.InnerText.Replace(JRNPLAN, PlanNofromTxt);