Question

我在arangodb中有这张测试图

节点：

[  { "_key": "A", "name": "A", "sector": "a"},
{ "_key": "B", "name": "B", "sector": "a"},
{ "_key": "C1", "name": "C1", "sector": "c"},
{ "_key": "C2", "name": "C2", "sector": "c"},
{ "_key": "C3", "name": "C3", "sector": "c"},
{ "_key": "C4", "name": "C4", "sector": "c"},
{ "_key": "D1", "name": "D1", "sector": "d"},
{ "_key": "D2", "name": "D2", "sector": "d"},
{ "_key": "E1", "name": "E1", "sector": "e"},
{ "_key": "E2", "name": "E2", "sector": "e"},
{ "_key": "E3", "name": "E3", "sector": "e"}]

边缘：

[{ "_from": "V/A","_to": "V/D1", "cat": [{"c":1,"s":3}] },
{ "_from": "V/A","_to": "V/D2", "cat": [{"c":1,"s":1}] },
{ "_from": "V/B","_to": "V/D2", "cat": [{"c":2,"s":1}] },
{ "_from": "V/D1","_to": "V/E1", "cat": [{"c":1,"s":8}] }, 
{ "_from": "V/D1","_to": "V/E2", "cat": [{"c":1,"s":4}] },
{ "_from": "V/D2","_to": "V/E2", "cat": [{"c":1,"s":3},{"c":2,"s":4}] },
{ "_from": "V/D2","_to": "V/E3", "cat": [{"c":2,"s":4}] },
{ "_from": "V/C1","_to": "V/B", "cat": [{"c":2,"s":5}] },
{ "_from": "V/C1","_to": "V/A", "cat": [{"c":1,"s":6}] },
{ "_from": "V/C2","_to": "V/A", "cat": [{"c":1,"s":2}] },
{ "_from": "V/C3","_to": "V/A", "cat": [{"c":1,"s":1}] },
{ "_from": "V/C4","_to": "V/A", "cat": [{"c":1,"s":1}] },
{ "_from": "V/C4","_to": "V/B", "cat": [{"c":2,"s":2}] } ]

它是更大图的简化部分（几乎一千个节点，数千个边）。请注意，在此示例中，每个边缘都有一个属性“ cat”作为类别对象的数组。实际上，在实际数据集中，每个边缘都是一个或多个网络的一部分。有22个网络/类别。在此工作示例中，只有两个，1和2。每个边都是一个类别的一部分，但D2-> E3是这两个类别中唯一的一个边缘。

问题：我必须遍历图，方法是从给定的顶点开始，过滤/选择选定类别（实际数据中的网络）及其相关顶点的边线。当然，要避免循环和重复的顶点或边。

示例：从B开始并选择类别2，我需要返回以下集合： v：[B，D2，E2，E3，C1，C4]和 e：[{B-> D2，D2-> E2，D2-> E3，C1-> B，C4-> B]

在AQL中，我尝试了以下各种过滤器：

FOR v, e, p IN 0..3 any "nodes/D2" edges OPTIONS {bfs: true, uniqueVertices: 'global'}
  //Here, the filter for cat 2  ?
return p

什么都没做（当然，我是Arango的新手）。

问题1：如何构造过滤器？

问题2：如何像上面的示例一样格式化结果？更准确地说（每个数组中对象的顺序无关紧要）：

[
  nodes: [{name:"B",sector:"a"}, {name:"D2",sector:"d"}, {name:"E2",sector:"e"}, ...]
  edges: [{source: "B", target: "D2", s:1}, {source: "D2", target: "E2", s:4}, ...]
]

感谢帮助。

Answer 1

1）为了过滤"c":2中的条目cat，对于路径（p.edges[*]）的所有边，必须检查c属性是否为（ .c数组（cat）的.cat[*]）包含值[2]。

因此，在访问子属性数组IN时，我们使用p.edges[*].cat[*].c运算符。

FILTER [2] IN p.edges[*].cat[*].c

2）return格式也可以通过访问以下子属性来调整：

return {'nodes':{'name':v.name,'sector':v.sector},'edges':{'source':e._from,'target':e._to, 's': e.cat[*].s}}

调整后的查询为：

FOR v, e, p IN 0..3 any "V/D2" edges
FILTER [2] IN p.edges[*].cat[*].c
return {'nodes':{'name':v.name,'sector':v.sector},'edges':{'source':e._from,'target':e._to, 's': e.cat[*].s}}

遍历Arangodb图，边缘进行数组过滤

1 个答案: