Bash-从文件读取行时打印第一和第二列

Question

我有一个如下的测试文件。 （但是实际文件有1000余行和许多列）

@Version

我要按以下方式打印此文件。

apple,2
mango,5
coconut,10

我尝试将I have apple and the count is 2 I have mango and the count is 5 I have coconut and the count is 10 与while read line一起使用，但没有获得实际输出。 有人可以帮我吗？

Answer 1

您可以像这样使用awk：

awk -F, '{print "I have", $1, "and the count is", $2}' file

I have apple and the count is 2
I have mango and the count is 5
I have coconut and the count is 10

尽管建议使用awk，但是如果您正在寻找bash循环，请使用：

while IFS=, read -r f c; do
    echo "I have $f and the count is $c"
done < file

Answer 2

这里是sed中的一位。用相关的字符串替换每行的开头和逗号：

$ sed 's/^/I have /;s/,/ and the count is /' file
I have apple and the count is 2
I have mango and the count is 5
I have coconut and the count is 10

Answer 3

如果文件很小，则可以使用read来分隔行。

while IFS=, read fruit count; do
  echo "I have $fruit and the count is $count"
done < file.txt

对于较大的文件，使用bash进行迭代效率不高，而像awk这样的文件读取整个文件会更合适。