Question

我将数字及其类型存储在oracle DB的单个列中。我想使用sql拆分它们并返回给用户。

例如ABC-1234 ABC是类型数字是

到目前为止，我已经尝试过了。是否要输入ABC或BN或XY或GF

  SELECT 'ABC-1234' TET_NUMBER FROM DUAL
  UNION ALL
  SELECT 'XY - 87686876' TET_NUMBER FROM DUAL
  UNION ALL  
  SELECT ' BN-345345' TET_NUMBER FROM DUAL
  UNION ALL   
    SELECT ' GF - 16666788789789' TET_NUMBER FROM DUAL
  UNION ALL   
    SELECT '987654' TET_NUMBER FROM DUAL

SELECT regexp_substr(TET_NUMBER, '[^-]+', 1, 1) AS PARTBEFORE- 

SELECT regexp_substr(TET_NUMBER, '[^-]+', 1, 1) AS PARTAFTER-

预期产量

ABC 1234
XY  87686876
BN  345345
GF  16666788789789

Answer 1

在这里：第一部分选择一个“单词”（\ w），第二部分选择一堆“数字”（\ d）。 WHERE子句可避免非字母行。

SQL> with test as
  2  (SELECT 'ABC-1234' TET_NUMBER FROM DUAL
  3   UNION ALL
  4   SELECT 'XY - 87686876' TET_NUMBER FROM DUAL
  5   UNION ALL
  6   SELECT ' BN-345345' TET_NUMBER FROM DUAL
  7   UNION ALL
  8   SELECT ' GF - 16666788789789' TET_NUMBER FROM DUAL
  9   UNION ALL
 10   SELECT '987654' TET_NUMBER FROM DUAL
 11  )
 12  select tet_number,
 13    regexp_substr(tet_number, '\w+') first_part,
 14    regexp_substr(tet_number, '\d+') second_part
 15  from test
 16  where regexp_like(tet_number, '[[:alpha:]]+')
 17  ;

TET_NUMBER           FIRST_PART      SECOND_PART
-------------------- --------------- ---------------
ABC-1234             ABC             1234
XY - 87686876        XY              87686876
 BN-345345           BN              345345
 GF - 16666788789789 GF              16666788789789

SQL>

[编辑：如OP注释中所述，如果输入字符串更改，该怎么办]

没什么；您将调整正则表达式，例如

 <snip>
 14  select
 15    tet_number,
 16    regexp_substr(tet_number, '\w+', 1, 1) first_part,
 17    regexp_substr(tet_number, '\w+', 1, 2) second_part
 18  from test
 19  where regexp_like(tet_number, '[[:alpha:]]+');

TET_NUMBER           FIRST_PART      SECOND_PART
-------------------- --------------- ---------------
ABC-1234             ABC             1234
XY - 87686876        XY              87686876
 BN-345345           BN              345345
 GF - 16666788789789 GF              16666788789789
ABC-1W234            ABC             1W234

sql regexp_substr在连字符前后获取字符串

1 个答案: