在AsyncResult上调用get()会使结果无效

时间:2018-08-09 20:46:48

标签: celery

在尝试First steps with Celery中的示例时,我发现与class a { public: enum {test = 0}; }; class b { public: enum {test = 1}; }; class c { public: enum {test = 2 < 3 ? a::test : b::test}; }; int main() { int v = c::test; } get()的调用顺序有关的意外行为。

下面的两个代码示例使用的是来自First steps with Celery的经过稍微修改的task.py,并且我的Celery worker进程在后台运行:

ready()

此代码执行一个任务,并尝试通过第二个from celery import Celery app = Celery('tasks', backend='rpc://', broker='pyamqp://guest@localhost//') @app.task def add(x, y): return x + y 对象查找结果,但它会爆炸:

AsyncResult

但是,通过交换import tasks, celery, time r0 = tasks.add.delay(1,1) time.sleep(.1) print('r0 result', r0.get(1)) # '2', expected print('r0 ready?', r0.ready()) # 'True', expected r1 = celery.result.AsyncResult(r0.id) print('r1 ready?', r1.ready()) # 'False', not expected! print('r1 result', r1.get(1)) # raises celery.exceptions.TimeoutError get(),代码按预期运行:

ready()

这是怎么回事?

0 个答案:

没有答案
相关问题