Question

我正在使用php从musql数据库返回员工信息。我正在使用number_format（）方法以带格式的逗号返回薪水，但是在返回数据时，所有员工的薪水都相同。如何获取php以从employee表中返回个人薪水？

PHP / MySQL

   <?php

    require_once("db.php");

    $sql = "SELECT `*` FROM `employees`";
    $results = mysqli_query($connect, $sql) or die(mysql_error());
    $row = mysqli_fetch_array($results, MYSQL_BOTH) or die(mysql_error());
    $salary = $row['salary']; 
    $rows_sal = number_format($salary); 

    echo("<table>");
    while($row = mysqli_fetch_array($results, MYSQL_BOTH))
    {
        echo("<tr>");
        echo "<td>" . $row['empid'] . '</td>' .
             "<td>" . $row['lastname'] . '</td>' .
             "<td>" . $row['firstname'] . '</td>' .
             "<td>" . $row['department'] . '</td>' .
             "<td>" . $row['position'] . '</td>' .
             "<td>" . $rows_sal . '</td>'; 


        echo '</br>';

        echo('</tr>');
    }


    echo("</table>");
    ?>

Answer 1

number_format在数组上不起作用。这样做：

<?php

    require_once("db.php");

    $sql = "SELECT `*` FROM `employees`";
    $results = mysqli_query($connect, $sql) or die(mysql_error());
    $row = mysqli_fetch_array($results, MYSQL_BOTH) or die(mysql_error());
    //$salary = $row['salary'];
    //$rows_sal = number_format($salary);

    echo("<table>");
    while($row = mysqli_fetch_array($results, MYSQL_BOTH))
    {
        echo("<tr>");
        echo "<td>" . $row['empid'] . '</td>' .
             "<td>" . $row['lastname'] . '</td>' .
             "<td>" . $row['firstname'] . '</td>' .
             "<td>" . $row['department'] . '</td>' .
             "<td>" . $row['position'] . '</td>' .
             "<td>" . number_format($row['salary']) . '</td>';


        echo '</br>';

        echo('</tr>');
    }


    echo("</table>");
?>

Answer 2

那是因为您正在使用foreach循环之外的薪水。（而且，顺便说一句，您将表的第一行遗漏了。）

在我建议您如何做之前，让我解释一下您的实际代码所发生的情况：（遵循注释）

   <?php

    require_once("db.php");

    $sql = "SELECT `*` FROM `employees`";
    $results = mysqli_query($connect, $sql) or die(mysql_error());

    //here you're asking THE FIRST row:
    $row = mysqli_fetch_array($results, MYSQL_BOTH) or die(mysql_error()); 
    $salary = $row['salary']; 
    //so $rows_sal is the first salary. All this have nothing to do with the iteration below.
    $rows_sal = number_format($salary); 

    echo("<table>");

    //here you're asking for the next results (leaving 1st row outside the table!)
    while($row = mysqli_fetch_array($results, MYSQL_BOTH)) 
    {
        echo("<tr>");
        echo "<td>" . $row['empid'] . '</td>' .
             "<td>" . $row['lastname'] . '</td>' .
             "<td>" . $row['firstname'] . '</td>' .
             "<td>" . $row['department'] . '</td>' .
             "<td>" . $row['position'] . '</td>' .

             //and here you're referencing the value set before the while.
             "<td>" . $rows_sal . '</td>'; 


        echo '</br>';

        echo('</tr>');
    }


    echo("</table>");
    ?>

现在这是您应该做的：（关注评论）

   <?php

    require_once("db.php");

    $sql = "SELECT `*` FROM `employees`";
    $results = mysqli_query($connect, $sql) or die(mysql_error());
    //don't ask for results yet! 

    echo("<table>");
    while($row = mysqli_fetch_array($results, MYSQL_BOTH)) //including 1st row
    {
        //now $row is EACH row, NOW you can format your salary:
        $salary = $row['salary']; 
        $rows_sal = number_format($salary); 
        echo("<tr>");
        echo "<td>" . $row['empid'] . '</td>' .
             "<td>" . $row['lastname'] . '</td>' .
             "<td>" . $row['firstname'] . '</td>' .
             "<td>" . $row['department'] . '</td>' .
             "<td>" . $row['position'] . '</td>' .
             "<td>" . $rows_sal . '</td>';
        echo '</br>';
        echo('</tr>');
    }


    echo("</table>");
    ?>

希望有帮助。

使用nymber_format使用mysql和php检索员工工资

2 个答案: