Question

我一直收到一条相同的错误消息（即使就在昨天一切正常。）从那时起，代码中没有任何更改。

这是代码本身：

x = [1, 4, 34, 56, 8, 5, 8, 6, 5, 12, 89, 23]  

z = int(input('Please eneter a number to check: ')    
if x.count(z) >= **2 :** *This is where it gives me a syntax error*        
    print('There are:', x.count(z), 'numbers of', z, 'in the list')    
elif x.count(z) > 0 < 2:        
    print('This number is unique in the list')
else:
    print('There is no such number in the list')

有什么想法为什么会发生？

Answer 1

我不确定您遇到了什么语法错误，因为您没有明确声明它。但是我相信您错过了z变量的右括号。这是固定的代码，它对我有用：

x = [1, 4, 34, 56, 8, 5, 8, 6, 5, 12, 89, 23]

z = int(input('Please eneter a number to check: '))

if x.count(z) >= 2 :
    print('There are:', x.count(z), 'numbers of', z, 'in the list')
elif x.count(z) > 0 < 2:
    print('This number is unique in the list')
else:
    print('There is no such number in the list')

Python-语法错误“ if语句”

1 个答案: