Question

我有以下DataFrame：

FACTORY_ID  SUPPLIER_ID DELIVERY_DATETIME
A   1   05/09/2015 11:00
A   1   05/09/2015 11:00
A   2   05/09/2015 11:00
A   2   08/09/2015 11:00
A   1   08/09/2015 11:00
A   1   08/09/2015 11:00
A   1   08/09/2015 11:00
A   2   08/09/2015 11:00
A   2   13/09/2015 11:00
A   3   13/09/2015 11:00
A   3   13/09/2015 11:00
A   3   13/09/2015 11:00
A   3   13/09/2015 11:00
A   3   13/09/2015 11:00

我打算使用GroupBy子句进行转换以显示要呈现的数据的摘要视图。（DELIVERY_DATETIME是连接在一起并以逗号分隔的列。）在此示例中需要的结果：

FACTORY_ID  SUPPLIER_ID DELIVERY_DATETIME
A   1   05/09/2015  11:00:00 AM, 08/09/2015  11:00:00 AM
A   2   05/09/2015  11:00:00 AM, 13/09/2015  11:00:00 AM
A   3   13/09/2015  11:00:00 AM

尝试了GroupBy / drop_duplicates，但无法获得我想要的。我应该怎么做？

Answer 1

IIUC groupby和agg

newdf=df.groupby(['FACTORY_ID','SUPPLIER_ID']).DELIVERY_DATETIME.agg(['first','last'])
newdf.loc[newdf['first']==newdf['last'],'last']=''
newdf
Out[69]: 
                             first        last
FACTORY_ID SUPPLIER_ID                        
A          1            05/09/2015  08/09/2015
           2            05/09/2015  13/09/2015
           3            13/09/2015

Pandas Dataframe Groupby多列

1 个答案: