Question

我有从php生成的json数组。但是格式不是我想要的。我有相关的问题，但不是我想要的格式。请在下面查看我做了什么并尝试过vs我想要的

    //////////////
$data variable array
///////////////

Array
    (
        [0] => Array
            (
                [id] => 2
                [start_date] => 2018-05-17 08:40
                [end_date] => 2018-05-17 09:00
            )

        [1] => Array
            (
                [id] => 3
                [start_date] => 2018-05-17 08:40
                [end_date] => 2018-05-17 09:00
            )
      )

这就是我所做的

$array[] = $data;
echo json_encode($array);

输出

[
 {"id":2,"start_date":"2018-05-17 08:40","end_date":"2018-05-17 09:00"},
 {"id":3,"start_date":"2018-05-17 08:40","end_date":"2018-05-17 09:00"}
]

这是我尝试过的

$array["data"] = $data;
echo json_encode($array);

输出

{"data":
 {"id":2,"start_date":"2018-05-17 08:40","end_date":"2018-05-17 09:00"},
 {"id":3,"start_date":"2018-05-17 08:40","end_date":"2018-05-17 09:00"}
}

我想要的输出

{
  "data": [
             {"id":2,"start_date":"2018-05-17 08:40","end_date":"2018-05-17 09:00"},
             {"id":3,"start_date":"2018-05-17 08:40","end_date":"2018-05-17 09:00"}
          ]
}

Answer 1

我没有使用<React.Fragment> <ul>{arr.map(item => <MyAppChild key={item.Name} Name={item.Name} Roughness={item.Roughness} Thickness={item.Thickness} />)}</ul>; <ul><ProductNameSave onChance ={fields => this.handleChange(fields)}/></ul>; </React.Fragment>，而是将“数据”放入一个数组，然后将另一个数据放入$array["data"]。

$data

上面的代码将输出如下内容：

$array = array("data" => $data);
$enData = json_encode($array); //encoding array to json
$deData = json_decode($enData, true); //decoding array

print_r($deData);

，如果您这样做：

Array
(
    [data] => Array
        (
            [id] => 3
            [start_date] => 2018-05-17 08:40
            [end_date] => 2018-05-17 09:00
        )

)

Answer 2

您需要先将$data设置为数组。

例如：

$data[] = ["id" => 2, "start_date" => "2018-05-17 08:40", "end_date" => "2018-05-17 09:00"];

$array["data"] = $data;
echo json_encode($array);

哪个返回：

{
  "data":[
           {"id":2,"start_date":"2018-05-17 08:40","end_date":"2018-05-17 09:00"}
         ]
}

Answer 3

您必须先构建一个数组，然后构建一个对象。见下文

$array = [
    [
        "id" => 2,
        "start_date" => "2018-05-17 08:40",
        "end_date" => "2018-05-17 09:00"
    ],
    [
        "id" => 3,
        "start_date" => "2018-05-17 08:40",
        "end_date" => "2018-05-17 09:00"
    ]
];
$data["data"] = $array;
echo json_encode($data);

Answer 4

似乎您是从sql输出循环中获取$ data的：

$array = ["data"=>[]];// initialize $array outside your loop

while($data = mysqli_fetch_assoc($result)){
    $array['data'][] = $data;  // push $data into $array['data']
}

echo json_encode($array);

我无法将json数组格式化为所需的格式

4 个答案: