使用带有箭头功能参数的filter()方法

时间:2018-08-18 13:04:36

标签: javascript filter arrow-functions

我已经了解了如何使用filter,但是看到此练习的答案是:Eloquent JavaScript使我感到困惑(单击“查看解决方案”时,您可以看到代码。之间的区别:

let counted = countBy(text, char => {
  let script = characterScript(char.codePointAt(0));
  return script ? script.direction : "none";
}).filter(({name}) => name != "none");

和:

let counted = countBy(text, char => {
    let script = characterScript(char.codePointAt(0));
    return script ? script.direction : "none";
}).filter(name => name != "none"); //The difference is here and when I tried this, it did not work

我所熟悉的是使用... .filter(something => condition);,它将返回满足上述条件的原始数组中所有项目的数组。我尝试将上面的代码更改为... .filter(script => script.name != "none")并成功。那么({name})到底是怎么做的而不必键入那么长的内容?

1 个答案:

答案 0 :(得分:1)

实际上是对象的破坏。无需将对象x传递到过滤器中然后与x.name进行比较,而是直接对name进行了破坏。

.filter(({name}) => name != "none");

等效于

.filter(x => x.name != "none");

有关解构here

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