Question

我收到此错误消息：

DELETE语句与REFERENCE约束冲突 “ FK_FieldMapper_Field”。数据库“ SCAM”中发生了冲突，表“ dbo.FieldMapper”的“ FieldID”列。

我有一些具有给定字段数量的accesshelpers。这些字段可由多个访问助手使用。.

删除accesshelper时，需要检查给定fields中的accesshelper是否被其他accesshelpers使用。如果是的话，我将删除accesshelper，但不要删除这些字段，因为那样会破坏其他accesshelper。我该怎么办？

到目前为止，这是我自己提出的。

USE [SCAM]
GO

SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO

ALTER PROCEDURE [dbo].[deleteAccessHelperById]

@Id int
AS
BEGIN

    SET NOCOUNT ON;

    DECLARE @projectIds TABLE (id int);
    INSERT INTO @projectIds ([id]) SELECT dbo.AccessHelperMapper.ProjectID FROM dbo.AccessHelperMapper WHERE dbo.AccessHelperMapper.AccessHelperID = @Id;

    DELETE dbo.AccessHelperMapper  WHERE dbo.AccessHelperMapper.AccessHelperID = @Id;

    DECLARE @fieldIds TABLE (id int);

    INSERT INTO @fieldIds ([id]) SELECT dbo.FieldMapper.FieldID FROM dbo.FieldMapper WHERE dbo.FieldMapper.AccessHelperID = @Id;


    DECLARE @AHfields TABLE (id int)
    Insert into @AHfields 
    Select fids.id from dbo.FieldMapper, @fieldIds as fids
    where dbo.FieldMapper.AccessHelperID != @Id
    and fids.id != dbo.FieldMapper.FieldID;

    delete dbo.FieldMapper where dbo.FieldMapper.AccessHelperID = @Id and dbo.FieldMapper.FieldID IN (SELECT d.id FROM @AHfields as d);
    delete dbo.Field where dbo.Field.ID in (SELECT g.id FROM  @AHfields as g);
    delete dbo.AccessHelper where dbo.AccessHelper.ID = @Id;


END

Answer 1

尝试以下代码。希望这就是您想要的：

USE [SCAM]
GO

SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO

ALTER PROCEDURE [dbo].[deleteAccessHelperById]

@Id int
AS
BEGIN

SET NOCOUNT ON;

DELETE dbo.AccessHelperMapper  WHERE dbo.AccessHelperMapper.AccessHelperID = @Id;

DECLARE @fieldIds TABLE (id int);

INSERT INTO @fieldIds ([id]) SELECT dbo.FieldMapper.FieldID FROM dbo.FieldMapper WHERE dbo.FieldMapper.AccessHelperID = @Id
AND dbo.FieldMapper.FieldID NOT IN (SELECT DISTINCT dbo.FieldMapper.FieldID FROM dbo.FieldMapper WHERE dbo.FieldMapper.AccessHelperID != @Id);

delete dbo.FieldMapper where dbo.FieldMapper.AccessHelperID = @Id --and dbo.FieldMapper.FieldID IN (SELECT d.id FROM @fieldIds as d);
delete dbo.Field where dbo.Field.ID in (SELECT g.id FROM  @fieldIds as g);
delete dbo.AccessHelper where dbo.AccessHelper.ID = @Id;


END

Answer 2

首先，您需要进行事务处理，因为部分数据更改无法单独应用。

ALTER PROCEDURE [dbo].[deleteAccessHelperById]
  @Id int
AS
BEGIN
    SET NOCOUNT ON;

    DECLARE @fieldIds TABLE (id int);

    BEGIN TRY
      BEGIN TRAN

      DELETE ahm
      FROM dbo.AccessHelperMapper ahm 
      WHERE ahm.AccessHelperID = @Id;

      DELETE fm
        OUTPUT DELETED.fieldID
        INTO @fieldIds(id)
      FROM dbo.FieldMapper fm
      WHERE fm.AccessHelperID = @Id 

      DELETE f
      FROM dbo.Field f
      WHERE exists(select 1 from @fieldIDs fid where fid.ID = f.ID)
        and not exists(
          select 1 from dbo.FieldMapper fm
          where fm.fieldID = f.ID 
             and fm.AccessHelperID != @ID  -- redundant, may be removed.
        )

      DELETE ah
      FROM dbo.AccessHelper ah
      where ah.ID = @Id

      COMMIT TRAN
    END TRY
    BEGIN CATCH
      IF XACT_STATE() IN (1, -1)
        ROLLBACK TRAN

      THROW;
    END CATCH
END

存储过程。检查是否在另一个表中使用了约束

2 个答案: