Question

我正在将matlab代码移植到python，并遇到下面的代码。看起来它创建了矩阵，但是我不确定矩阵的形状是什么。有人可以帮助我理解这段代码的含义，特别是'...'和']。^ 2'吗？

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        g {
            pointer-events: bounding-box;     
            //not working on FF
        }
        #mobile:hover .flip {
            transform-origin:55% 50%;
            -moz-transform-origin:55% 50%;
            animation: flip_left 1.6s forwards;
        }
        @keyframes flip_left {
          0% {transform: perspective(2000px) rotateY(90deg) skewY(-1deg)}
          30% {transform:perspective(2000px) rotateY(-25deg) skewY(-0.8deg)}
          50% {transform:perspective(2000px) rotateY(20deg) skewY(0.8deg)}
          70% {transform:perspective(2000px) rotateY(-10deg) skewY(-0.8deg)}
          100% {transform:perspective(2000px) rotateY(0deg)}
        }
    </style>
    <!-- Generator: Sketch 51.2 (57519) - http://www.bohemiancoding.com/sketch -->
    <title>Mobile solutions</title>
    <desc>Created with Sketch.</desc>
    <defs></defs>
    <g id="mobile" stroke="none" stroke-width="1" fill="none" fill-rule="evenodd">
        <g id="MS_HP_Usecase_Based_Page-Desktop-2A" transform="translate(-766.000000, -418.000000)" stroke="#00A0DF" stroke-width="1.25">
            <g id="Asset-5" transform="translate(766.000000, 418.000000)">
                <g class="flip">
                <rect id="Rectangle-path" stroke-linecap="round" stroke-linejoin="round" x="12.35" y="7.41" width="15.32" height="25.33" rx="2.03"></rect>
                <circle id="Oval" stroke-linecap="round" stroke-linejoin="round" cx="20.01" cy="28.72" r="1.58"></circle>
                <path d="M18.43,10.72 L21.48,10.72" id="Shape" stroke-linecap="round" stroke-linejoin="round"></path>
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                <circle id="Oval" cx="19.67" cy="19.67" r="19.04"></circle>
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</svg>

Answer 1

这是逐项运算符，将每个项的幂赋值为2。换句话说，它等效于以下代码：

somevarialbe = [var1^2...
            var2^2...
            var3^2];

...表示代码中的下一行。因此，它等效于以下代码：

somevarialbe = [var1^2 var2^2 var3^2];

[val ...]。^ 2是什么意思？

1 个答案: