Question

我的项目中有以下模型

class TicketCounter(models.Model):
    user = models.ForeignKey(User, on_delete=models.CASCADE)
    ticket_counter_name = models.CharField(max_length=100, default="")

class TicketCategory(models.Model):
    user = models.ForeignKey(User, on_delete=models.CASCADE)
    ticket_category_name = models.CharField(max_length=100, default="")
    ticket_category_rate = models.CharField(max_length=100, default="")


class WorkerToTicketCounter(models.Model):
    user = models.ForeignKey(User, on_delete=models.CASCADE)
    ticket_counter = models.ForeignKey(TicketCounter, related_name="workers")
    worker = models.ForeignKey(User, related_name='ticket_counter')
    worker_to_ticket_counter_is_deleted = models.BooleanField(default=False)


class TicketCounterToCategory(models.Model):
    user = models.ForeignKey(User, on_delete=models.CASCADE)
    ticket_counter = models.ForeignKey(TicketCounter, related_name="categories")
    ticket_category = models.ForeignKey(TicketCategory)

每个TicketCounter将有一个worker（用户）和TicketCategory个。当工作人员登录到Android应用程序时。他将必须获取诸如email first_name和'last_name'之类的详细信息。我是用下面的序列化器完成的。

class MeSerializer(serializers.ModelSerializer):
    class Meta:
        model = User
        fields = (
            'pk',
            'first_name',
            'last_name',
            'email',
    )

在我的应用程序中，不仅需要详细信息，而且需要与他关联的TicketCounter。所以我像下面一样添加了ticket_counter

class MeSerializer(serializers.ModelSerializer):
    ticket_counter = serializers.SerializerMethodField(read_only=True)

    class Meta:
        model = User
        fields = (
            'pk',
            'first_name',
            'last_name',
            'email',
            'ticket_counter',
    )

    def get_ticket_counter(self, user):
        qs = user.ticket_counter.filter(worker_to_ticket_counter_is_deleted=False)
        if qs.exists() and hasattr(qs.first().ticket_counter, 'ticket_counter_name'):
            return qs.first().ticket_counter.ticket_counter_name
        return "--"

但是现在我需要在ticket_counter中的对象列表中获取该MeSerializer的关联类别。可能吗？

Django嵌套的序列化器，用于不直接相关的名称

0 个答案: