添加if / else过滤器

Question

我有以下脚本：

SELECT * 
FROM (
          SELECT distinct web_product_source_id, recipe_id,  cos_score,
                row_number() over (partition by web_product_source_id order by cos_score desc) as rnk 
          FROM (
                    SELECT  web_product_source_id, recipe_id, max(cos_score) cos_score
                    FROM edw_sandbox.combined_with_product_details_ouput_cleaned
                    WHERE web_supercat_source_id = 'cookware'
                    GROUP BY 1,2
                ) a
    ) b
WHERE rnk <= 20
ORDER BY web_product_source_id, rnk;

我想在“ WHERE”语句中添加if else语句。如果web_product_source_id id包含以下任何一项（“炊具”，“设置”等），我希望数据排在前20名或前40名

Sudo代码：

if 'set' or 'cookware' in web_product_source_id id: pull top 40 ranks
else: pull top 20 ranks and cos_score >= .7