Postgres libpq：CREATE VIEW无法识别参数占位符

Question

请参阅下面的示例用法。这将返回错误：

错误：绑定消息提供1个参数，但准备好的语句“”需要0

paramValues[0] = "40";
res = PQexecParams(connection,
    "CREATE VIEW myview AS (SELECT u FROM myuser u WHERE karma > $1)",
    1,      /* one param */
    NULL,   /* let the backend deduce param type */
    paramValues,
    NULL,   /* don't need param lengths since text */
    NULL,   /* default to all text params */
    0);     /* results format (0 = text; 1 = binary) */