将数据从一个视图控制器传递到另一个(图像)

时间:2018-09-08 08:49:50

标签: swift

错误:

线程1:EXC_BAD_INSTRUCTION(代码= EXC_I386_INVOP,子代码= 0x0)

目标控制器

var getImage = UIImage()
var name = String()
var gender = String()
var house = String()
var ancestry = String()

override func viewDidLoad() {
    super.viewDidLoad()
    imageView.image = (charData.image)as! UIImage
    nameLabel.text! = name
    houseLabel.text! = house

    // Do any additional setup after loading the view.
}

源控制器

var charactersData = [Character]()

override func viewDidLoad() {
    super.viewDidLoad()
    loadData()
}

func loadData()
{
    DispatchQueue.main.async {
        Alamofire.request("http://hp-api.herokuapp.com/api/characters").responseJSON(completionHandler: {
            (response) in
            switch response.result
            {
            case.success(let value):
                let json = JSON(value)
                print(json)
                json.array?.forEach({
                    (character) in
                    let character = Character(name: character["name"].stringValue, house:character["house"].stringValue,image:character["image"].stringValue, gender: character["gender"].stringValue, ancestry: character["ancestry"].stringValue)
                    self.charactersData.append(character)
                })
                self.tableView.reloadData()
            case.failure(let error):
                print(error.localizedDescription)
            }
        })
    }
}


override func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {

    return charactersData.count
}


override func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
    let cell = tableView.dequeueReusableCell(withIdentifier: "cell", for: indexPath) as! CharTableViewCell

    cell.nameLabel.text = "Name: " +  charactersData[indexPath.row].name
    cell.houseLabel.text = "House: " + charactersData[indexPath.row].house

    if let imageURL = URL(string: self.charactersData[indexPath.row].image) {
        DispatchQueue.global().async {
            let data = try? Data(contentsOf: imageURL)
            if let data = data {
                let image = UIImage(data: data)
                DispatchQueue.main.async {
                    cell.charImageView.image = image
                }
            }
        }
    }
    return cell
}
override func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) {
    let hpc = storyboard?.instantiateViewController(withIdentifier: "CharDetails") as? CharDetailsViewController
    hpc?.getImage =  (charactersData[indexPath.row].image) as! UIImage
    hpc?.name = charactersData[indexPath.row].name
    hpc?.house = charactersData[indexPath.row].house
    self.navigationController?.pushViewController(hpc!, animated: true)
}

我正在尝试将图像传递给另一个控制器,但似乎收到该错误,有人可以帮助我。除图像外,其他所有其他数据(如名称和房屋)都正确传递。请让我知道在哪里进行更改

2 个答案:

答案 0 :(得分:2)

这可能有效:

override func viewDidLoad() {
    super.viewDidLoad()

    imageView.image = getimage   // change this in view did load method
}

答案 1 :(得分:0)

您做错了(这不是UIImage,这是URL字符串,因此您可以使用此url字符串下载图像):

hpc?.getImage =  (charactersData[indexPath.row].image) as! UIImage

请将UIImage替换为String,因为这不是UIImage,这是用于下载图像的String URL

因此,您必须将getImage变量UIImage更改为String并将此String传递给此变量

var getImage = String()

hpc?.getImage =  (charactersData[indexPath.row].image) as! String

之后,再次从另一个控制器的URL下载此图像,但是这种方法不好,因此您可以按照以下方法进行操作:

您还有另一种选择,例如下载图像时保存Character Struct并在didselect时传递它

过程:

  1. 在角色结构/模型中添加新变量,例如图像
  2. 在Struct / Model中调用API时分配下载的图片
  3. didSelect
  4. 时将此图像传递给另一个控制器