有人可以帮我上传图像时遇到问题吗?
PHP
<?php
$msg="";
$db=mysqli_connect("localhost","root","root","man");
if(isset($_POST['submit'])) {
$fileName=$_FILES['uploadfile']['name'];
$fileTmpName=$_FILES['uploadfile']['tmp_name'];
$folder='images/';
move_uploaded_file($fileTmpName,$folder.$fileName);
$sql=mysqli_query($db,"INSERT INTO manimages(image) VALUES ($fileName)");
}
?>
HTML
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="UTF-8">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
<meta http-equiv="X-UA-Compatible" content="ie=edge">
<title>Uploading Images</title>
</head>
<body>
<form action="" method="POST">
<input type="file" name="uploadfile">
<input type="submit" name="submit" value="upload image">
</form>
</body>
</html>
错误提示:未定义索引:第5行C:\ wamp64 \ www \ ftest \ index.php中的uploadfile 和注意:未定义的索引:在第6行的C:\ wamp64 \ www \ ftest \ index.php中上传文件
答案 0 :(得分:1)
要允许表单上传文件,您应指定正确的job
属性,默认情况下为$('#content *').each(function(_, el) {
el.getAttributeNames().forEach(el.removeAttribute.bind(el));
});
console.log($('#content')[0].outerHTML)
,应将其更改为<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="content">
<span id="span" data-span="a" aria-describedby="span">span</span>
<p class="a b c" style="color:black;">paragraph</p>
</div>
。
尝试一下:
enctype
现在您可以访问application/x-www-form-urlencoded
超全局变量multipart/form-data
,因此不会引发未定义的索引错误。
答案 1 :(得分:0)
您的form
标签不完整,用于上传图像的外观应为:
<form action="" method="post" enctype="multipart/form-data">
请记住,如果您正在使用文件上传控件,则必须将enctype
设置为multipart/form-data