Question

text = "hellovision hey creator   yoyo  b  creator great  publisher"

我想从文本中提取创作者的名字和出版者的名字。

结果将是

creator = hellovision嘿，悠悠

发布者=很好

如何使用正则表达式获取文本？

我需要使用span（）..

这是我的代码。

def preprocess2(text):

    text_list = test.split(' ')
    lyricist = []
    composer = []
    music_arranger = []
    temp = []
    lyricist.clear()
    composer.clear()
    music_arranger.clear()
    for i in range(0, len(text_list)):
        if text_list[i] == 'creator':
            print(len(text_list))
            for a in range(0, i-1):
                temp.append(text_list[a])
            lyricist.append(''.join(temp))
            temp.clear()
            for b in range(0, i+1):
                print(b)
                text_list.pop(b)
                print(len(text_list))
            break
        elif text_list[i] == 'pulisher':
            for a in range(0, i-1):
                temp.append(text_list[a])
            composer.append(''.join(temp))
            temp.clear()
            for b in range(0, i+1):
            text_list.pop(b)
        break
    i = i +1
return text_list

Answer 1

如果使用带有捕获组的正则表达式拆分数组，拆分时的值也将传递到输出数组中。

然后，您可以循环查找'creator'或'publisher'，并在每种情况下，将前一个条目传递到适当的集合中。

const text = "hellovision hey creator   yoyo  b  creator great  publisher"

const splitArr = text.split(/(creator|publisher)/)

const creators = [], publishers = []

let i = -1, len = splitArr.length

while(++i < len){
  if(splitArr[i] == "creator") creators.push(splitArr[i-1].trim())
  else if(splitArr[i] == "publisher") publishers.push(splitArr[i-1].trim())
}

console.log("creators: ", creators)
console.log("publishers: ", publishers)

使用正则表达式匹配字符串

1 个答案: