使用排列和组合的智商问题

时间:2018-09-11 15:07:36

标签: math permutation iq

使用数字54730的所有数字,可以创建小于70000且5的倍数的5个不同的5位数字?

1 个答案:

答案 0 :(得分:0)

您将加起来:

5xxx0 = 3! = 6 combinations that start with 5 and end with 0
4xxx0 = 3! = 6 combinations that start with 4 and end with 0
4xxx5 = 3! = 6 combinations that start with 4 and end with 5
3xxx0 = 3! = 6 combinations that start with 3 and end with 0
3xxx5 = 3! = 6 combinations that start with 3 and end with 5

6*5 = 30 total combinations

注意: 您不会执行7xxx0或7xxx5,因为它们会大于70000

来源: https://en.wikipedia.org/wiki/Combination#Number_of_k-combinations_for_all_k

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