我尝试从数据库中循环多个值,并且每次我单击菜单上的特定项目时,即使函数在循环内,Javascript也只会捕获数据库中出现的第一个值,即使我单击最后一个项目,第一个项目仍显示...如何解决?这是我的代码。 (结果显示在最上面,我没有包括在内)
<?php
$res = mysqli_query($db,"select * from menu where Restaurant_id='$id' order by Food_name asc") or die("Error: " . mysqli_error($db));
while($rows = mysqli_fetch_array($res)){
$f_id = $rows['Menu_id'];
$fname = $rows['Food_name'];
$fprice = $rows['Price'];
?>
<div class="col-12 helv menu rounded">
<ul class="nav navbar-nav navbar-expand-md">
<li class="nav-item"><img class="rounded" src="data:image/gif;base64,R0lGODlhAQABAIAAAHd3dwAAACH5BAAAAAAALAAAAAABAAEAAAICRAEAOw==" alt="Generic placeholder image" width="180" height="180"></li>
<li class="nav-item marginleft">
<br>
<input id="foodname" value="<?php echo $fname;?>" style="display: none;"><h5><b><?php echo $fname;?></b></h1></input><br>
<input id="foodprice" value="<?php echo $fprice;?>" style="display: none;"><h5>Php <?php echo $fprice;?>.00</h1></input>
</li>
<li class="nav-item" style="position: absolute; margin-left: 90%">
<button class="fa fa-plus btn btn-danger" onclick="add()"> Add</button>
</li>
</ul>
<br>
</div>
<script>
function add() {
var fdname = document.getElementById("foodname").value;
var fdprice = document.getElementById("foodprice").value;
document.getElementById("display").innerHTML = fdname;
document.getElementById("display1").innerHTML = fdprice;
}
</script>
<?php } ?>
答案 0 :(得分:1)
<?php
// As Jeto said, you should use prepared statement
$res = mysqli_query($db,"select * from menu where Restaurant_id='$id' order by Food_name asc") or die("Error: " . mysqli_error($db));
while($rows = mysqli_fetch_array($res)){
$f_id = $rows['Menu_id'];
$fname = $rows['Food_name'];
$fprice = $rows['Price'];
?>
<div class="col-12 helv menu rounded">
<ul class="nav navbar-nav navbar-expand-md">
<li class="nav-item"><img class="rounded" src="data:image/gif;base64,R0lGODlhAQABAIAAAHd3dwAAACH5BAAAAAAALAAAAAABAAEAAAICRAEAOw==" alt="Generic placeholder image" width="180" height="180"></li>
<li class="nav-item marginleft">
<br>
<input class="foodname" value="<?php echo $fname;?>" style="display: none;"><h5><b><?php echo $fname;?></b></h1></input><br>
<input class="foodprice" value="<?php echo $fprice;?>" style="display: none;"><h5>Php <?php echo $fprice;?>.00</h1></input>
</li>
<li class="nav-item" style="position: absolute; margin-left: 90%">
<button class="fa fa-plus btn btn-danger" onclick="add('<?php echo $fname;?>', <?php echo $fprice;?>)"> Add</button>
</li>
</ul>
<br>
</div>
<?php } ?>
<script>
function add(fdname, fdprice) {
document.getElementById("display").innerHTML = fdname;
document.getElementById("display1").innerHTML = fdprice;
}
</script>
答案 1 :(得分:0)
首先查询while查询之前其中有多少项
$res = mysqli_query($db,"select * from menu where Restaurant_id='$id' order by Food_name asc") or die("Error: " . mysqli_error($db));
$count_of_items = mysqli_num_rows($res);
然后运行while查询,然后根据项目数在表单内运行for循环
for($x=0;$x<count($count_of_items); $x++){
<input id="foodname" value="<?php echo $fname[$x];?>" style="display: none;"><h5><b><?php echo $fname[$x];?></b></h1></input><br>
<input id="foodprice" value="<?php echo $fprice[$x];?>" style="display: none;"><h5>Php <?php echo $fprice[$x];?>.00</h1></input>
}
答案 2 :(得分:0)
还有更多错误。
请选中此https://stackoverflow.com/a/12889416/3742228
您进行的每个循环都会创建另一个名为“ add”的JS函数。如果创建3个名为“ add”的函数,则在编写add()时要调用哪个函数? :)
对于您的代码,还有更多解决方案,但这取决于您要执行的操作。看看这个:
<?php
$res = mysqli_query($db,"select * from menu where Restaurant_id='$id' order by Food_name asc") or die("Error: " . mysqli_error($db));
while($rows = mysqli_fetch_array($res)){
$f_id = $rows['Menu_id'];
$fname = $rows['Food_name'];
$fprice = $rows['Price'];
?>
<div class="col-12 helv menu rounded">
<ul class="nav navbar-nav navbar-expand-md">
<li class="nav-item"><img class="rounded" src="data:image/gif;base64,R0lGODlhAQABAIAAAHd3dwAAACH5BAAAAAAALAAAAAABAAEAAAICRAEAOw==" alt="Generic placeholder image" width="180" height="180"></li>
<li class="nav-item marginleft">
something here
</li>
<li class="nav-item" style="position: absolute; margin-left: 90%">
<button class="fa fa-plus btn btn-danger" foodName="<?php echo $fname;?>" foodPrice="<?php echo $fprice;?>" onclick="add(this)"> Add</button>
</li>
</ul>
<br>
</div>
<?php } ?>
<script>
function add(e) {
var fdname = e.getAttribute("foodName");
var fdprice = e.getAttribute("foodPrice");
document.getElementById("display").innerHTML = fdname;
document.getElementById("display1").innerHTML = fdprice;
}
</script>