Question

我需要获取所选party_id的用户名，但是我需要插入而不是 party_id，我尝试使用嵌套子查询，但始终陷入括号。

我选择了这个选项，而不是第二个选择gm.party_id：

SELECT * FROM (
  select gm.party_id, sum(gm.game_out)
  from game_record gm
  where gm.party_id in (
    select cs.party_id
    from casino_users cs
    where cs.parent_id=get_party_id_from_promo(619)
  ) 
  group by party_id
  order by sum(game_out) desc
)
WHERE ROWNUM <= 10;

我需要插入此选择：

select username
from casino_users
where party_id in (
  select cs.party_id
  from casino_users cs
  where cs.parent_id=get_party_id_from_promo(619)
)

我还具有从party_id返回用户名的功能，但是当我尝试对其进行编译时，在第一次选择时会收到无效的标识符错误。

FUNCTION get_top_ten_highscore(p_promo_code number) RETURN WEAK_CUR IS
 resault_set weak_cur;

begin

 open resault_set for

     SELECT * FROM (
       select username_from_id (gm.party_id) as party_id, sum(gm.game_out)
       from game_record gm
       where gm.party_id in (
         select cs.party_id
         from casino_users cs
         where cs.parent_id=get_party_id_from_promo(619)
       ) 
       group by party_id
       order by game_out desc)
    WHERE ROWNUM <= 10;
    return  resault_set ;

end get_top_ten_highscore;

Answer 1

您可以使用JOIN

    SELECT 
      select gm.party_id, sum(gm.game_out), cs.username
      from game_record gm
      INNER JOIN  casino_users cs ON cs.parent_id=get_party_id_from_promo(619)
      WHERE ROWNUM <= 10;
      group by gm.party_id, cs.username
      order by sum(game_out) desc

Answer 2

from collections import defaultdict as dd

nested_dict = dd(lambda: dd(lambda: dd(list)))
for m in model.objects.all():
    nested_dict[m.Country][m.State][m.City].append(m.Street)

将select插入select

2 个答案: