Question

简介

我在捕获InputMismatchException时遇到问题。当我已经搜索InputMismatchException时，我已经阅读了该网站上显示在首页上的所有主题。在阅读这些主题时，我找到了我的一个问题的答案；该答案告诉我，我必须在导入语句中添加import java.util.InputMismatchException;。但是，我遇到了一个其他问题，在任何解决方案中都找不到。最接近的其他问题是this one。我认为他和我有同样的问题，但是该解决方案对我不起作用。

我的问题

我正在制作一个类，演示我制作的ProductionWorker数据类型。我想测试所有输入，以确保它们是可以按预期操作的有效输入。我试图获得双倍的薪资输入，如果输入错误，我想被要求再次尝试输入。说我不小心输入了“加里”而不是我的工资。我想了一次try-catch-finally最终可以工作，但是进入catch块之后，我仍然收到InputMismatchException ...

控制台输出

run:
What is your name: gary
Please enter employee number: 88-m
Incorrect employee ID, please check it and try again.
Enter employee number: 888-m
Please enter hire date as "MM/DD/YYYY": 07/14/1994
Please enter shift (1 for day shift, 2 for night shift.: 2
Please enter rate of pay: $h
Rate of pay can only be digits.
Exception in thread "main" java.util.InputMismatchException
Examples: 30.00; 22.10; 7.25; 10.00
    at java.util.Scanner.throwFor(Scanner.java:864)
Please enter rate of pay: $ at java.util.Scanner.next(Scanner.java:1485)
    at java.util.Scanner.nextDouble(Scanner.java:2413)
    at programmingchallengeq1.ProgrammingChallengeQ1.main(ProgrammingChallengeQ1.java:69)
Picked up _JAVA_OPTIONS: -Xmx512m
C:\Users\nikru\AppData\Local\NetBeans\Cache\8.2\executor-snippets\run.xml:53: Java returned: 1
BUILD FAILED (total time: 15 seconds)

在我看来，由于该打印语句显示在控制台中，因此我将其放入catch块中，并且我认为如果将其放入catch块中，则异常不会使程序崩溃。我不知道我在做什么错...

代码

/*
 * To change this license header, choose License Headers in Project Properties.
 * To change this template file, choose Tools | Templates
 * and open the template in the editor.
 */
package programmingchallengeq1;

import java.util.Scanner;
import java.util.regex.*;
import java.util.InputMismatchException;

public class ProgrammingChallengeQ1 {

    public static void main(String[] args) 
    {
        Scanner kb = new Scanner(System.in);
        final int SHIFT_LENGTH = 12;

        ProductionWorker workman = new ProductionWorker();
        System.out.print("What is your name: ");
        workman.set_name(kb.nextLine());
        System.out.print("Please enter employee number: ");
        // ask user for id and save it to workman
        workman.set_id(kb.nextLine());

        // while loop ensures that employee num matches specific format
        while (check_id(workman) == false)
        {
            System.out.print("Incorrect employee ID, please check it and" +
                    " try again.\n" + "Enter employee number: ");
            workman.set_id(kb.nextLine());
        }

        System.out.print("Please enter hire date as \"MM/DD/YYYY\": ");
        // ask user for date of hire and save it to workman
        workman.set_hire_date(kb.nextLine());
        // attempt to ensure a valid date was input with while loop
        while(check_date(workman) == false)
        {
            System.out.println("Date not recognized, please check date" +
                    " and try again.\n" + "Enter hire date as \"MM/DD/YYY\": ");
            workman.set_hire_date(kb.nextLine());
        }
        System.out.print("Please enter shift (1 for day shift, 2 for night"+
                " shift.: ");
        workman.set_shift(kb.nextInt());
        // the while loop checks if a correct value is stored for shift
        while(workman.get_shift() != 1 && workman.get_shift() != 2)
        {
            System.out.print("Unrecognized shift. Please enter a 1 for" +
                    " day shift, or 2 for night shift: ");
            workman.set_shift(kb.nextInt());
        }
        System.out.print("Please enter rate of pay: $");
        // attempt to ensure a valid rate of pay is input with try-catch
        // boolean is the exit condition for while loop, which only breaks
        // if the input is valid
        boolean valid_input = false;
        while (valid_input != true)
        {
            try
            {
                workman.set_pay_rate(kb.nextDouble());
                valid_input = true;
            }
            catch(InputMismatchException ex)
            {
                //System.out.println(ex.getMessage());
                System.out.print("Rate of pay can only be digits.\nExamples:" +
                    " 30.00; 22.10; 7.25; 10.00\nPlease enter rate of pay: $");
            }
            finally
            {
                workman.set_pay_rate(kb.nextDouble());
            }
        }

    }

    public static boolean check_id(ProductionWorker wrkr)
    {
        // creating a regex pattern to check against input employee ID
        // to avoid inputting error
        String id_format = "\\d{3}-[a-m]";
        Pattern id_pattern = Pattern.compile(id_format);
        // check id against compiled regex pattern and save to a bool
        Matcher id_matcher = id_pattern.matcher(wrkr.get_id());
        boolean id_matches = id_matcher.matches();
        return id_matches;
    }
    public static boolean check_date(ProductionWorker wrkr)
    {
        //same concept as in check_id()
        String date_format = "\\d{2}/\\d{2}/\\d{4}";
        Pattern date_pattern = Pattern.compile(date_format);
        Matcher date_matcher = date_pattern.matcher(wrkr.get_hire_date());
        boolean date_matches = date_matcher.matches();
        return date_matches;
    }
}

感谢所有帮助，谢谢！

Answer 1

您也在nextDouble()块中运行finally，因此无论发生什么情况，它都将在此时失败。基本上，第一个失败的调用不会消耗数据，因此第二个调用不会等待新的用户输入，它会立即尝试使用已经存在的输入并再次失败。

您必须明确使用该行来解决此问题：

Scanner sc = new Scanner(System.in);
try {
    sc.nextDouble();
} catch (InputMismatchException e) {
    System.out.println("Oops, something went wrong...");
    sc.nextLine();
    sc.nextDouble();
}

我删除了finally块，因为我不明白为什么在第一次尝试成功后为什么要重试该操作。

Answer 2

finally
{
  workman.set_pay_rate(kb.nextDouble());
}

您的异常在这里被抛出，并且没有被捕获，因为该语句没有被try \ catch包围

InputMismatchException被捕获后使程序崩溃

2 个答案: