Question

我想为汽车列表开发一个排序演示。我正在使用数据表来显示汽车清单。实际上我想按汽车颜色对列表进行排序。这里不按字母顺序排序。我想使用我的自定义排序顺序，如Red car先行，然后是Blue等等。

为此，我尝试使用Java Comparator和Comparable，但它只允许按字母顺序排序。

因此，任何人都可以指导我实现使用该技术的方式，以便排序变得更快。

class Car implements Comparable<Car>
{
    private String name;
    private String color;

    public Car(String name, String color){
        this.name = name;
        this.color = color;
    }

    //Implement the natural order for this class
    public int compareTo(Car c) {
        return name.compareTo(c.name);
    }

    static class ColorComparator implements Comparator<Car> {
        public int compare(Car c1, Car c2) {
            String a1 = c1.color;
            String a2 = c2.color;
            return a1.compareTo(a2);
        }
    }

    public static void main(String[] args) {
        List<Car> carList = new ArrayList<>();
        List<String> sortOrder = new ArrayList<>();

        carList.add(new Car("Ford","Silver"));
        carList.add(new Car("Tes","Blue"));
        carList.add(new Car("Honda","Magenta"));

        sortOrder.add("Silver");
        sortOrder.add("Magenta");
        sortOrder.add("Blue");

        // Now here I am confuse how to implement my custom sort             
    }
}

Answer 1

我建议您为汽车颜色创建一个枚举，而不是使用字符串，枚举的自然顺序将是您声明常量的顺序。

public enum PaintColors {
    SILVER, BLUE, MAGENTA, RED
}

和

 static class ColorComparator implements Comparator<CarSort>
 {
     public int compare(CarSort c1, CarSort c2)
     {
         return c1.getColor().compareTo(c2.getColor());
     }
 }

您将String更改为PaintColor，然后在main中将您的汽车列表变为：

carList.add(new CarSort("Ford Figo",PaintColor.SILVER));

...

Collections.sort(carList, new ColorComparator());

Answer 2

这个怎么样：

List<String> definedOrder = // define your custom order
    Arrays.asList("Red", "Green", "Magenta", "Silver");

Comparator<Car> comparator = new Comparator<Car>(){

    @Override
    public int compare(final Car o1, final Car o2){
        // let your comparator look up your car's color in the custom order
        return Integer.valueOf(
            definedOrder.indexOf(o1.getColor()))
            .compareTo(
                Integer.valueOf(
                    definedOrder.indexOf(o2.getColor())));
    }
};

原则上，我同意使用enum是一种更好的方法，但是这个版本更灵活，因为它允许您定义不同的排序顺序。

<强>更新

Guava已将此功能添加到其Ordering类中：

List<String> colorOrder = ImmutableList.of("red","green","blue","yellow");
final Ordering<String> colorOrdering = Ordering.explicit(colorOrder);
Comparator<Car> comp = new Comparator<Car>() {
    @Override
    public int compare(Car o1, Car o2) {
        return colorOrdering.compare(o1.getColor(),o2.getColor());
    }
};

这个版本的冗长一点。

再次更新

Java 8使得Comparator更加冗长：

Comparator<Car> carComparator = Comparator.comparing(
        c -> definedOrder.indexOf(c.getColor()));

Answer 3

比较者排队......

List<Object> objList = findObj(name);
Collections.sort(objList, new Comparator<Object>() {
    @Override
    public int compare(Object a1, Object a2) {
        return a1.getType().compareToIgnoreCase(a2.getType());
    }
});

Answer 4

我认为可以这样做：

class ColorComparator implements Comparator<CarSort>
{
    private List<String> sortOrder;
    public ColorComparator (List<String> sortOrder){
        this.sortOrder = sortOrder;
    }

    public int compare(CarSort c1, CarSort c2)
    {
        String a1 = c1.getColor();
        String a2 = c2.getColor();
        return sortOrder.indexOf(a1) - sortOrder.indexOf(a2);
     }
 }

对于排序使用此：

Collections.sort(carList, new ColorComparator(sortOrder));

Answer 5

我必须做类似于Sean和ilalex的回答但是我有太多的选项来明确定义排序顺序，只需要将某些条目浮动到列表的前面...按指定的（非自然的）顺序。
希望这对其他人有帮助。

public class CarComparator implements Comparator<Car> {

    //sort these items in this order to the front of the list 
    private static List<String> ORDER = Arrays.asList("dd", "aa", "cc", "bb");

    public int compare(final Car o1, final Car o2) {
        int result = 0;
        int o1Index = ORDER.indexOf(o1.getName());
        int o2Index = ORDER.indexOf(o2.getName());
        //if neither are found in the order list, then do natural sort
        //if only one is found in the order list, float it above the other
        //if both are found in the order list, then do the index compare
        if (o1Index < 0 && o2Index < 0) result = o1.getName().compareTo(o2.getName());
        else if (o1Index < 0) result = 1;
        else if (o2Index < 0) result = -1;
        else result = o1Index - o2Index;
        return result;
    }

//Testing output: dd,aa,aa,cc,bb,bb,bb,a,aaa,ac,ac,ba,bd,ca,cb,cb,cd,da,db,dc,zz
}

Answer 6

在Java 8中，您可以执行以下操作：

首先需要一个枚举：

public enum Color {
    BLUE, YELLOW, RED
}

汽车类：

public class Car {

    Color color;

    ....

    public Color getColor() {
        return color;
    }

    public void setColor(Color color) {
        this.color = color;
    }
}

然后，使用您的汽车列表，您可以简单地执行：

Collections.sort(carList, Comparator:comparing(CarSort::getColor));

Answer 7

将一个枚举类型定义为

public enum Colors {
     BLUE, SILVER, MAGENTA, RED
}

将color的数据类型从String更改为Colors 将getter的返回类型和参数类型以及颜色的setter方法更改为Colors

定义比较器类型如下

static class ColorComparator implements Comparator<CarSort>
{
    public int compare(CarSort c1, CarSort c2)
    {
        return c1.getColor().compareTo(c2.getColor());
    }
}

向List添加元素后，通过将列表和比较器对象作为参数传递来调用Collection的sort方法

即Collections.sort(carList, new ColorComparator()); 然后使用ListIterator打印。

全班实施如下：

package test;

import java.util.ArrayList;
import java.util.Collections;
import java.util.Comparator;
import java.util.List;    
import java.util.ListIterator;

public class CarSort implements Comparable<CarSort>{

    String name;
    Colors color;

    public CarSort(String name, Colors color){
        this.name = name;
        this.color = color;
    } 

    public String getName() {
        return name;
    }
    public void setName(String name) {
        this.name = name;
    }
    public Colors getColor() {
        return color;
    }
    public void setColor(Colors color) {
        this.color = color;
    }

    //Implement the natural order for this class
    public int compareTo(CarSort c)
    {
        return getName().compareTo(c.getName());
    }

    static class ColorComparator implements Comparator<CarSort>
    {
        public int compare(CarSort c1, CarSort c2)
        {
            return c1.getColor().compareTo(c2.getColor());
        }
    }

    public enum Colors {
         BLUE, SILVER, MAGENTA, RED
    }

     public static void main(String[] args)
     {
         List<CarSort> carList = new ArrayList<CarSort>();
         List<String> sortOrder = new ArrayList<String>();

         carList.add(new CarSort("Ford Figo",Colors.SILVER));
         carList.add(new CarSort("Santro",Colors.BLUE));
         carList.add(new CarSort("Honda Jazz",Colors.MAGENTA));
         carList.add(new CarSort("Indigo V2",Colors.RED));
         Collections.sort(carList, new ColorComparator());

         ListIterator<CarSort> itr=carList.listIterator();
         while (itr.hasNext()) {
            CarSort carSort = (CarSort) itr.next();
            System.out.println("Car colors: "+carSort.getColor());
        }
     }
}

Answer 8

我会做这样的事情：

List<String> order = List.of("Red", "Green", "Magenta", "Silver");

Comparator.comparing(Car::getColor(), Comparator.comparingInt(c -> order.indexOf(c)))

所有学分归@Sean Patrick Floyd：）

Answer 9

仅使用简单的循环：

public static void compareSortOrder (List<String> sortOrder, List<String> listToCompare){
        int currentSortingLevel = 0;
        for (int i=0; i<listToCompare.size(); i++){
            System.out.println("Item from list: " + listToCompare.get(i));
            System.out.println("Sorting level: " + sortOrder.get(currentSortingLevel));
            if (listToCompare.get(i).equals(sortOrder.get(currentSortingLevel))){

            } else {
                try{
                    while (!listToCompare.get(i).equals(sortOrder.get(currentSortingLevel)))
                        currentSortingLevel++;
                    System.out.println("Changing sorting level to next value: " + sortOrder.get(currentSortingLevel));
                } catch (ArrayIndexOutOfBoundsException e){

                }

            }
        }
    }

并在列表中排序

public static List<String> ALARMS_LIST = Arrays.asList(
            "CRITICAL",
            "MAJOR",
            "MINOR",
            "WARNING",
            "GOOD",
            "N/A");

如何使用Comparator定义自定义排序顺序？

9 个答案: