Question

编程新手。

我在Java中有一个类，我正在尝试编写此程序，但是它不停地打印，甚至还困扰着我的浏览器！（我正在使用在线IDE）

我的说明：问：你有多爱我？ 10以下：错误答案等于10以上=好的答案

我知道该怎么做，但我不希望我每次写答案时都停止程序。我希望程序继续运行直到我有10岁以上。因此，我始终可以输入，直到10分之10以上为止。

这是我的台词：

import java.util.Scanner;
public class Main {
  public static void main(String[] args) {
    Scanner input = new Scanner (System.in);
    System.out.println ("how much do you love me out of 10");
    int num1 = input.nextInt();

    while (true) 
    if (num1 <= 9) {
    System.out.println("Wrong answer");
    }
       else {
       System.out.println ("Good answer");
       }
 }
}

Answer 1

This should work:

import java.util.Scanner;

public class Main {
    public static void main(String[] args) {
        Scanner scanner = new Scanner (System.in);
        System.out.println ("Out of 10, how much do you love me?");
        int input = 0
        while (input <= 9) {
            input = scanner.nextInt();
            if (input <= 9) {
                System.out.println("Wrong answer");
            } else {
                System.out.println("Good answer");
            }
        }
    }
}

Explanation: It loops until input is less not less than or equal to 9 (while (input <= 9)). Each time through the loop, it gets input and acts on it.

Hope this helps!

Answer 2

First off, you need to move the int num1 = input.nextInt(); statement inside your while loop, this will allow for a new input every time the while loop loops (iterates).

Second, if you are looking to run the program until num1 >= 10, then you could implement it in two ways.

while(num1 < 10) {
    num1 = input.nextInt();

    if(num1 >= 10) {
        System.out.println("Good answer");
    } else {
        System.out.println("Wrong answer");
    }
}

or using the keyword break,

while(true) {
    num1 = input.nextInt();

    if(num1 >= 10) {
        System.out.println("Good answer");
        break;
    } else {
        System.out.println("Wrong answer");
    }
}

break simply escapes the loop it resides in when called

Hoped this helped

尝试使用循环时无限打印

2 个答案: