Question

我有这样的列表，并想将它们转换为地图

val myList = List(
    "IDENTIFIER, a, b, c", 
    "IDENTIFIER, d, e,f",
    "INFORMATION, a, b, c",
    "INFORMATION, d, e, f"
)

预期输出：

Map[String,List[String]] = Map(IDENTIFIER -> List(a b c, d e f), INFORMATION -> List(a b c, d e f))`

Answer 1

提供列表：

val myList = List(
    "IDENTIFIER, a, b, c", 
    "IDENTIFIER, d, e, f",
    "INFORMATION, a, b, c",
    "INFORMATION, d, e, f"
)

使用

myList.map(_.split(",")).groupBy(_.head).mapValues(_.map(_.tail.mkString(" ").trim))

在Scala REPL中：

scala> myList.map(_.split(",")).groupBy(_.head).mapValues(_.map(_.tail.mkString(" ").trim))
res91: scala.collection.immutable.Map[String,List[String]] = Map(IDENTIFIER -> List(a  b  c, d  e  f), INFORMATION -> List(a
  b  c, d  e  f))

scala>

Scala组通过从列表进行映射

1 个答案: