Question

数据数组

[
 {group: 'a', tab: "1", name: 'input1'},
 {group: 'b', tab: "1", name: 'input2'},
 {group: 'b', tab: "1", name: 'input3'},
 {group: 'c', tab: "2", name: 'input4'},
 {group: 'a', tab: "1", name: 'input5'},
 {group: 'c', tab: "2", name: 'input6'},
];

在我的应用程序中，每个数组元素（其中有50多个）都是一个输入，它属于一组（a，b或c）和制表符（1、2等）。我想做的是检查一个选项卡有多少组，得到一个看起来像这样的对象或数组：

 [
      {tab1:{groups: ["a", "b"]}},
      {tab2:{groups: ["c"]}},
    ]

Answer 1

您只需使用Array.reduce()来创建地图并按Tab键将其分组，地图上的Object.values()将为您提供所需的结果。

let arr =[ {group: "a", tab: "1", name: "input1"}, {group: "b", tab: "1", name: "input2"}, {group: "b", tab: "1", name: "input3"}, {group: "c", tab: "2", name: "input4"}, {group: "a", tab: "1", name: "input5"}, {group: "c", tab: "2", name: "input6"}];

let result = Object.values(arr.reduce((a, {group, tab})=>{
  a[tab] = a[tab] || {["tab"+tab] : {group : []}};
  if(!a[tab]["tab"+tab].group.includes(group))
    a[tab]["tab"+tab].group.push(group);
  return a;
},{}));

console.log(result);

：

Answer 2

我们可以使用Set创建唯一的数组，并使用map操纵每个数组项，并使用filter从数组中删除元素。所以我要做的是：

获取标签的唯一列表。
映射列表以为每个选项卡创建一个新对象
1. 使用过滤器查找特定类型的标签
2. 映射该过滤器以仅获取组字母
3. 再次为一组唯一的组字母列表创建一个集合。
最后，新对象返回到第一个地图项，以获取项数组。

它看起来像这样：

let data = [
 {group: 'a', tab: "1", name: 'input1'},
 {group: 'b', tab: "1", name: 'input2'},
 {group: 'b', tab: "1", name: 'input3'},
 {group: 'c', tab: "2", name: 'input4'},
 {group: 'a', tab: "1", name: 'input5'},
 {group: 'c', tab: "2", name: 'input6'},
];

let tabs = [...new Set(data.map(itm => itm.tab))].map(tab => {
  return {
    ['tab' + tab]: {groups: [...new Set(data.filter(i => i.tab == tab).map(i => i.group))]}
  }
})

console.log(tabs)

Answer 3

您可以使用Map进行分组，并使用Set收集唯一值。

var data = [{ group: 'a', tab: '1', name: 'input1' }, { group: 'b', tab: '1', name: 'input2' }, { group: 'b', tab: '1', name: 'input3' }, { group: 'c', tab: '2', name: 'input4' }, { group: 'a', tab: '1', name: 'input5' }, { group: 'c', tab: '2', name: 'input6' }],
    result = Array.from(
        data.reduce(
            (m, { tab, group }) => m.set(tab, (m.get(tab) || new Set).add(group)),
            new Map
        ),
        ([tab, groups]) => ({ ['tab' + tab]: { groups: Array.from(groups) } })
    );
    
console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0; }

Answer 4

尝试下一个代码

const src = [
  { group: "a", tab: "1", name: "input1" },
  { group: "b", tab: "1", name: "input2" },
  { group: "b", tab: "1", name: "input3" },
  { group: "c", tab: "2", name: "input4" },
  { group: "a", tab: "1", name: "input5" },
  { group: "c", tab: "2", name: "input6" },
];

const convert = (src) => {
  const dst = [];
  Object.keys(src).forEach((item) => {
    const tab = `tab${src[item].tab}`;
    // Check if dst[tab] does not exist
    if (typeof (dst[tab]) === 'undefined') {
      dst[tab] = { groups: [] };
    }
    // Check if groups contains group
    if (!dst[tab].groups.includes(src[item].group)) {
      dst[tab].groups.push(src[item].group);
    }
  });
  return dst;
};

console.log(convert(src));

转换对象数组-一些数组和对象操作

4 个答案: