将json字符串转换为列表对象（json对象的索引号会影响转换）

Question

请看一下照片。

我在尝试将JSON字符串转换为列表对象时遇到困难。 经过故障排除后，我发现问题是由于Json索引（Number正在增加而不是按1,2,4,5,6,5601,5611 ..的顺序）。任何人都知道我如何将json转换为升序列表中的对象12345678910 ..（model [0]，model 1，model [2]，model [3] ....）

        using (StreamReader reader = new StreamReader(stream))
        {
            jsonstr = reader.ReadToEnd();
        }
        var settings = new JsonSerializerSettings
        {
            NullValueHandling = NullValueHandling.Ignore,
            MissingMemberHandling = MissingMemberHandling.Ignore
        };

        List<Notification> model = JsonConvert.DeserializeObject<List<Notification>>(jsonstr, settings).Where(m => m != null).ToList();

错误消息：

  

Newtonsoft.Json.JsonSerializationException：'无法反序列化当前JSON对象（例如{“ name”：“ value”}）为类型'System.Collections.Generic.List`1'，因为该类型需要JSON数组（例如[1,2,3]）正确反序列化。   要解决此错误，可以将JSON更改为JSON数组（例如[1,2,3]），也可以更改反序列化类型，使其成为普通的.NET类型（例如，不像整数这样的原始类型，也不像这样的集合类型数组或列表），可以从JSON对象反序列化。还可以将JsonObjectAttribute添加到类型中，以强制其从JSON对象反序列化。   路径'1'，第1行，位置5。'

JSON结果

{"1":{"confirmation_status":"Rejected","createDateTime":"2018-08-31 16:58:58.087","logID":1,"notification_message":"\"There is a change request for \"Vital\" to be approved.\"","read_status":"true","recipient":"68d9dffc-b3be-4527-a89a-829b76abf754","sender":"01a94cf4-5df4-4097-b6ea-d929170de1e7","senderDetails":"Adeline Tan "},"6":{"confirmation_status":"Rejected","createDateTime":"2018-08-31 16:58:58.087","logID":6,"notification_message":"\"There is a change request for \"Vital\" to be approved.\"","read_status":"true","recipient":"68d9dffc-b3be-4527-a89a-829b76abf754","sender":"01a94cf4-5df4-4097-b6ea-d929170de1e7","senderDetails":"Adeline Tan "},"5601":{"confirmation_status":"Pending","createDateTime":"2018-08-31 16:58:58.087","logID":5601,"notification_message":"\"There is a change request for \"Vital\" to be approved.\"","read_status":"true","recipient":"68d9dffc-b3be-4527-a89a-829b76abf754","sender":"01a94cf4-5df4-4097-b6ea-d929170de1e7","senderDetails":"Adeline Tan "},"5611":{"confirmation_status":"Pending","createDateTime":"2018-08-31 16:58:58.087","logID":5611,"notification_message":"\"There is a change request for \"Vital\" to be approved.\"","read_status":"true","recipient":"68d9dffc-b3be-4527-a89a-829b76abf754","sender":"01a94cf4-5df4-4097-b6ea-d929170de1e7","senderDetails":"Adeline Tan "}}

通知类别：

 public class Notification
{
    public string confirmation_status { get; set; }
    public string createDateTime { get; set; }
    public int logID { get; set; }
    public string notification_message { get; set; }
    public string read_status { get; set; }
    public string recipient { get; set; }
    public string sender {get; set; }
    public string senderDetails { get; set; }
}

Answer 1

显示的JSON是对象而不是数组

您最有可能想要

List<Notification> model = JsonConvert.DeserializeObject<Dictionay<string,Notification>>(jsonstr, settings)
.Select(kvp => kvp.Value)    
.Where(m => m != null)
.OrderBy(m => m.logID)
.ToList();

将JSON转换为字典并将值提取为所需的类型。