如何在listagg中使用chr(10)?

时间:2018-09-25 14:32:26

标签: oracle oracle11g

我需要在listagg中插入一个char(10),但是它不能按预期工作。

这是我写的脚本:

select ID, listagg(value , ';')within group (order by ID) as "value"
from DTA 
group by ID


Current Result
ID  |value      |
----|-----------|
1   |aaa;bbb;ccc|
2   |abc        |
3   |abe        |


Desired Result 

ID  |value          
----|------
1   |aaa            
    |bbb                
    |ccc            
----|------
2   |abc            
----|------
3   |abe

我尝试使用它,但是没有按预期工作。

select ID, listagg(value , chr(10))within group (order by ID) as "value"
from DTA 
group by ID

如何改善我的脚本?

3 个答案:

答案 0 :(得分:1)

您的代码正确。您需要一个能够显示换行符的工具:

WITH DTA AS (
  SELECT 1 AS ID, 'A' AS Value FROM dual
  UNION ALL
  SELECT 1 AS ID, 'B' FROM dual
)
select ID, listagg(value , chr(10))within group (order by ID) as "value"
from DTA 
group by ID;

db<>fiddle demo

输出:

ID  value
1   A
    B

答案 1 :(得分:0)

在下面的查询中使用PIVOT进行尝试,很难通过listagg实现chr(10)。

WITH sample_data AS (SELECT 1 ID,  'aaa' value FROM dual UNION ALL
                     SELECT 1 ID,  'bbb' value FROM dual UNION ALL
                     SELECT 1 ID,  'ccc' value FROM dual UNION ALL
                     SELECT 2 ID,  'abc' value FROM dual UNION ALL
                     SELECT 3 ID,  'abe' value FROM dual )

SELECT CASE WHEN row_number() OVER (PARTITION BY DTA_ID
                                    ORDER BY CASE 
                                                  WHEN column_name = 'VALUE' THEN 1
                                             END) = 1
                 THEN DTA_ID
       END "Current ID",
       vals "Result Value"
FROM (SELECT ID DTA_ID,
               VALUE 
        FROM   sample_data)
UNPIVOT (vals FOR column_name IN ("VALUE"))
ORDER BY DTA_ID;

答案 2 :(得分:0)

这可能会帮助您满足要求

select ID, listagg(value , || CHR (10)) within group (order by ID) as "value"
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