列长可以是十进制

时间:2018-09-25 17:58:59

标签: python pandas dataframe

我的问题是len(df)可以是小数点

len(DataFrame)

代码:

import pandas as pd
from sklearn import preprocessing ,model_selection ,svm
from sklearn.linear_model import LinearRegression

df = quandl.get('WIKI/GOOGL',authtoken = 
't_nBiw5yVx3CXs3Zsuco')


df = df[['Open','High','Low','Close','Volume']]
HL_pct = (df['High'] - df['Low']) / df['Low'] * 100
PCT_change = (df['Close'] - df['Open']) / df['Open'] * 100

df = ['Volume','HL_pct','PCT_change','Close']

print(len(df))
forcast_col  = df['Close']

1 个答案:

答案 0 :(得分:0)

如果您引用的是python函数len,则该函数将返回the number of items in an object。不能为十进制,因为项不能为十进制数字(即int的一半)。

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