Question

我正在尝试返回符合此条件的结果

与ProfileType和2个不同的ColorCode相同

我当前的查询返回所有ProfileType和ColorCodes

ProfileType | ColorCode

SPT1        | 8XYZ
SPT1        | 1XYZ
SPT2        | 4XYZ
SPT2        | 4XYZ
SPT3        | 4XYZ
SPT3        | 9XYZ
SPT4        | 4XYZ
SPT4        | 4XYZ

我只想从上述结果集中返回这些行，因为它们是相同的ProfileType，但是具有两个不同的ColorCodes

ProfileType | ColorCode
SPT1        | 8XYZ
SPT1        | 1XYZ
SPT3        | 4XYZ
SPT3        | 9XYZ

查询

SELECT. P.ProfileType, E.ColorCode,
FROM profilegroups AS PG
 INNER JOIN mfg.profiles AS P
         ON PG.id = P.pickgroup
 INNER JOIN exts AS E
         ON E.Profile = P.Profile
        AND E.ProductNumber IN ('XYZ123', 'MX231X')
        AND PG.DoProcess = 1 
        AND P.ProfileType IN ('SPT1','SPT2','SPT3','SPT4','SPTX2','SPT31', 'SPT90');

表格

ProfileGroups
    - id
Profiles 
    - Profile 
    - ProfileType 
    - PickGroup
Exts
    - Profile 
    - ColorCode

Profiles和Exts有一个主键Profile，它与Profiles表中的ProfileType是不同的

Answer 1

加入一个子查询，该子查询获取每种配置文件类型的不同颜色代码的数量，但仅返回具有一个以上颜色代码的颜色代码：

SELECT profileType
FROM Exts
GROUP BY profileType
HAVING COUNT(DISTINCT colorCode) > 1

完整查询如下：

SELECT. ProfileType, Color,
FROM profilegroups AS PG
 INNER JOIN mfg.profiles AS P
         ON PG.id = P.pickgroup
 INNER JOIN exts AS E
         ON E.ProfileType = P.ProfileType
 INNER JOIN (
    SELECT profile
    FROM Exts
    GROUP BY profile
    HAVING COUNT(DISTINCT colorCode) > 1) M 
        ON M.profile = P.profile
WHERE   E.ProductNumber IN ('XYZ123', 'MX231X')
        AND PG.DoProcess = 1 
        AND P.ProfileType IN ('SPT1','SPT2','SPT3','SPT4','SPTX2','SPT31', 'SPT90')

Answer 2

尝试一下：

select profileType, colorCode
from (select distinct profileType, colorCode from table) a
group by profileType
having count(*) > 1;

返回一列中值相等而另一列中值不同的行

2 个答案: