我无法为我的项目创建过滤器，因此每个人都可以使用它们，所有这些我都找到了jersey 2.0的示例，但是当我尝试在我的项目中使用时根本无法使用。我无法弄清楚如何使用jersey 1.19拦截URL上的REST服务。我已经在这个项目上工作了大约一个月，所以我拒绝升级到jersey 2.0，除非这很容易。该服务现在在云上。 https://pets2018.herokuapp.com/controllers.jsp
package com.service.controllers;
import java.util.List;
import java.util.StringTokenizer;
import javax.ws.rs.core.Response;
import javax.ws.rs.ext.Provider;
import com.service.exceptions.WebApplicationException;
import com.sun.jersey.core.util.Base64;
import com.sun.jersey.spi.container.ContainerRequest;
import com.sun.jersey.spi.container.ContainerRequestFilter;
@Provider
public class AuthController implements ContainerRequestFilter {
private static final String AUTHORIZATION_HEADER_KEY = "Authorization";
private static final String AUTHORIZATION_HEADER_PREFIX = "Basic ";
private static final String CONTROLLERS_PREFIX = "test";
@Override
public ContainerRequest filter(ContainerRequest requestContext) {
if(requestContext.getPath().contains(CONTROLLERS_PREFIX)) {
System.out.println(requestContext.getBaseUri().getPath());
List<String> authHeader = requestContext.getRequestHeader(AUTHORIZATION_HEADER_KEY);
if(authHeader != null && authHeader.size() > 0) {
String authToken = authHeader.get(0);
authToken = authToken.replaceFirst(AUTHORIZATION_HEADER_PREFIX, "");
String decodedString = Base64.base64Decode(authToken);
StringTokenizer tokenizer = new StringTokenizer(decodedString, ":");
String username = tokenizer.nextToken();
String password = tokenizer.nextToken();
if("username".equals(username) && "password".equals(password)) {
}
}else {
Response unauthorizedStatus = Response.status(Response.Status.UNAUTHORIZED).entity("No puede ingresar a este servicio").build();
try {
throw new WebApplicationException(unauthorizedStatus);
} catch (WebApplicationException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
}else {
System.out.println("No se encuentra la palabra indicada en el URI requerido");
}
return null;
}
}