我想分组并显示在html表的单元格中逗号分隔的数据（数字）。我想根据它们的值对数据进行分组。因此，如果数字介于1到20之间，则它们将位于第一列，例如6,10,11,12,15,17。我如何轻松实现这一目标？谢谢。
我的代码是这样的：
<table class="tbstyle">
<tr>
<th>1-20</th>
<th>21-40</th>
<th>41-60</th>
<th>61-80</th>
<th>81-100</th>
</tr>
<?php
include ("config.php");
$sql = "SELECT Rpa, Rpb, Rpc, Rpd, Rpe, Rpf, Rpg, Rph, Rpi, Rpj, Rpk, Rpl, Rpm, Rpn, Rpo, Rpp, Rpq, Rpr FROM RpDb";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
while($row = $result->fetch_assoc())
{
//I am stuck in this part.
}
echo "</table>";
} else { echo "0 results"; }
$conn->close();
?>
</table>
答案 0 :(得分：2)
这是使用array_reduce的相对简单的解决方案：
$rows = array(
array(1, 30, 40, 22, 12, 14, 55, 68, 91, 80, 99, 23, 63, 61, 83),
array(8, 17, 59, 14, 93, 31, 57, 91, 29, 38, 54, 47, 28, 12, 15)
);
// replace this line with your while($row = $result->fetch_assoc())
foreach ($rows as $row) {
echo "<tr>";
sort($row);
$groups = array_reduce($row, function ($c, $v) { $c[(int)floor(($v-1) / 20)][] = $v; return $c; }, array());
for ($i = 0; $i < 5; $i++) {
echo "<td>" . implode(',', isset($groups[$i]) ? $groups[$i] : array()) . "</td>";
}
echo "</tr>\n";
}
输出：
<tr><td>1,12,14</td><td>22,23,30,40</td><td>55</td><td>61,63,68,80</td><td>83,91,99</td></tr>
<tr><td>8,12,14,15,17</td><td>28,29,31,38</td><td>47,54,57,59</td><td></td><td>91,93</td></tr>
答案 1 :(得分：1)
这是一个代码片段，可以完成我认为您要完成的工作。也许有更快的方法（循环更少），但是确实可以。
<?php
$borders = [20,40,60,80];
// some test data
$rows[] = ["Rpa" => 30, "Rpb" => 14, "Rpc" => 1, "Rpd" => 24];
$rows[] = ["Rpa" => 41, "Rpb" => 33, "Rpc" => 20, "Rpd" => 79];
$grouprows = []; // we'll need some array to re-structure your rows.
foreach($rows as $row) { // this is your while($row = $result->fetch_assoc())
$groups = []; // the former columns will be packed into "groups" (1-20, 21-40,..)
foreach($row as $column => $value) { // walk through all Rpa, Rpb, ...
foreach($borders as $i => $border) { // walk through the borders (<20, <40, <60,..)
if($value <= $border) { // if it fits into the current group/border, add it to that group
$groups[$border][] = "$column: $value";
break; // ..and don't look any further
}
}
ksort($groups); // sort the groups to be ascending
}
$grouprows[] = $groups; // add the just edited row to the main array
}
// actual output
echo "<table border=1>
<tr>
<th>1-20</th>
<th>21-40</th>
<th>41-60</th>
<th>61-80</th>
<th>81-100</th>
</tr>";
foreach($grouprows as $row) {
echo "<tr>\n";
$colcount = 0;
foreach($row as $col) {
if(is_array($col)) {
echo "\t<td>" . implode(", ",$col) . "</td>\n";
} else {
echo "\t<td></td>\n";
}
$colcount++;
}
// if we haven't filled all column yet (because there were no fitting values), add empty tds
for($colcount;$colcount<count($borders);$colcount++) {
echo "\t<td></td>\n";
}
echo "</tr>\n";
}
echo "</table>";
输出：
<table border=1>
<tr>
<th>1-20</th>
<th>21-40</th>
<th>41-60</th>
<th>61-80</th>
<th>81-100</th>
</tr>
<tr>
<td>Rpb: 14,Rpc: 1</td>
<td>Rpa: 30,Rpd: 24</td>
<td></td>
<td></td>
</tr>
<tr>
<td>Rpc: 20</td>
<td>Rpb: 33</td>
<td>Rpa: 41</td>
<td>Rpd: 79</td>
</tr>
</table>
答案 2 :(得分：1)
好吧，根据我对您问题的理解，您想从数据库中所有列中获取所有数字（数据），并将它们排序到表中，因此，这是有关如何执行此操作的示例：-
...
$num_list = array();
if ($result->num_rows > 0)
while($row = $result->fetch_assoc())
foreach ($row as $value)
array_push($num_list, $value);
//sort the numbers
sort($num_list);
//insert them into the table
for($i=1; $i<=100; $i+=20){
$res = "";
//store the numbers between these indexes into this string
foreach($num_list as $value)
if($value >= $i && $value < $i+20)
$res .= $value . ", ";
//remove the end comma
if(strlen($res) != 0)
$res = substr($res, 0, -1);
//echo the data
echo "<td>$res</td>\n";
}
...
编辑
我不理解这种说法。我想分组并显示用逗号分隔的数据（数字），因为您在下面的评论中说过，您不希望将逗号分隔一个单元格，因此，我尝试将结果划分为行，但不要将它们用逗号或其他任何东西分开，因此，让我们尝试在代码中进行一些更改，然后再插入for loop：-< / p>
...
$all_values = array();
//insert them into the table(old comment)
//insert them into the array(new comment)
for($i=1; $i<=100; $i+=20){
//insert an array into the array
array_push($all_values, array());
//store the numbers between these indexes into this array
foreach($num_list as $value)
if($value >= $i && $value < $i+20)
array_push($all_values[count($all_values)-1], $value);
}
//Getting the count of the longest group of numbers and sorting them
$longet_length = 0;
foreach($all_values as $value){
sort($value);
if(count($value) > $longet_length)
$longet_length = count($value);
}
//Finally insert them into the table
$current_index = 0;
while($current_index < $longet_length){
echo "<tr>\n";
foreach($all_values as $value)
if(count($value) > $current_index)
echo "<td>{$value[$current_index]}</td>\n";
else
echo "<td>Empty</td>\n";
echo "</tr>\n";
$current_index++;
}
...
答案 3 :(得分：1)
这是未经测试的，没有达到风口浪尖，但是我认为您想要实现的目标的基本逻辑就在那里。让我知道是否有任何问题，我将修改答案。
$row_nums = array_values($row);
asort($row_nums);
$grouped_scores = [];
foreach($row_nums as $num){
switch (true) {
case ($num <= 20):
$grouped_scores[1][] = $num;
break;
case ($num > 20 && $num <= 40):
$grouped_scores[2][] = $num;
break;
case ($num > 40 && $num <= 60):
$grouped_scores[3][] = $num;
break;
case ($num > 60 && $num <= 80):
$grouped_scores[4][] = $num;
break;
case ($num > 80):
$grouped_scores[5][] = $num;
break;
}
}
echo '<tr>';
foreach($grouped_scores as $score_array){
echo '<td>'.implode(',', $score_array).'</td>';
}
echo '</tr>';