Question

第一个数据帧是：

   data_date cookie_type   dau  next_dau  dau_7  dau_15
0   20181006    avg(0-d)  2288       NaN    NaN     NaN
1   20181006    avg(e-f)  2284       NaN    NaN     NaN
2   20181007    avg(e-f)  2296       100    NaN     NaN

第二个数据帧是：

  data_date cookie_type  next_dau
0  20181006    avg(e-f)       908
1  20181006    avg(0-d)       904

如何从第二个数据帧更新第一个数据帧的next_dau 我尝试了Combine_first和fillna，它们似乎不支持多重索引：

cols = ['data_date', 'cookie_type']

    if (frame1 is not None and not frame1.empty):
        frame1.set_index(cols)
        print(frame1)
        print(next_day_dau)
        frame1.combine_first(next_day_dau.set_index(cols))
        frame1.combine_first(dau_7.set_index(cols))
        frame1.combine_first(dau_15.set_index(cols))

然后我更新为：

frame1.index = frame1.data_date.astype(str) + frame1.cookie_type
        next_day_dau.index = next_day_dau.data_date.astype(str) + next_day_dau.cookie_type
        dau_7.index = dau_7.data_date.astype(str) + dau_7.cookie_type
        dau_15.index = dau_15.data_date.astype(str) + dau_15.cookie_type
        """frame1.loc[next_day_dau.index, "next_dau"] = next_day_dau.next_dau
        frame1.loc[dau_7.index, "dau_7"] = dau_7.dau_7
        frame1.loc[dau_15.index, "dau_15"] = dau_15.dau_15"""
        frame1.combine_first(next_day_dau)
        frame1.combine_first(dau_7)
        frame1.combine_first(dau_15)
        print(frame1)
        print(next_day_dau)

loc由于next_day_dau未包含frame1中的所有索引而引发错误，然后我尝试使用inplace = True组合并优先和fillna，所有方法均无效。

{'data_date': {'20181007avg(0-d)': 20181007, '20181007avg(e-f)': 20181007, '20181006avg(0-d)': 20181006, '20181006avg(e-f)': 20181006}, 'cookie_type': {'20181007avg(0-d)': 'avg(0-d)', '20181007avg(e-f)': 'avg(e-f)', '20181006avg(0-d)': 'avg(0-d)', '20181006avg(e-f)': 'avg(e-f)'}, 'dau': {'20181007avg(0-d)': 2288, '20181007avg(e-f)': 2284, '20181006avg(0-d)': 2288, '20181006avg(e-f)': 2284}, 'next_dau': {'20181007avg(0-d)': nan, '20181007avg(e-f)': nan, '20181006avg(0-d)': nan, '20181006avg(e-f)': nan}, 'dau_7': {'20181007avg(0-d)': nan, '20181007avg(e-f)': nan, '20181006avg(0-d)': nan, '20181006avg(e-f)': nan}, 'dau_15': {'20181007avg(0-d)': nan, '20181007avg(e-f)': nan, '20181006avg(0-d)': nan, '20181006avg(e-f)': nan}}
{'data_date': {0: '20181007', 1: '20181007'}, 'cookie_type': {0: 'avg(e-f)', 1: 'avg(0-d)'}, 'next_dau': {0: 2284, 1: 2288}}

Answer 1

您可以使用熊猫merge来解决用例。更多文档在这里： https://pandas.pydata.org/pandas-docs/stable/generated/pandas.DataFrame.merge.html

 print(t1)
  cookie_type  data_date  next_dau
0    avg(0-d)   20181006       1
1    avg(e-f)   20181006       2
2    avg(e-f)   20181007       NaN

    print(t2)
  cookie_type  data_date  next_dau
0    avg(e-f)   20181006       908
1    avg(0-d)   20181006       904
2    avg(e-f)   20181007       905

result = pd.merge(t1, t2, on=['data_date', 'cookie_type'])

  cookie_type  data_date  next_dau_x  next_dau_y
0    avg(0-d)   20181006         1         904
1    avg(e-f)   20181006         2         908
2    avg(e-f)   20181007         NaN       905

现在，要仅更新不更新Nan 值，可以使用where子句。

result['col'] = result['next_dau_x'].where(result['next_dau_x'].notnull(), result['next_dau_y'])

现在，删除不需要的列。

result = result.drop(['next_dau_x','next_dau_y'], axis=1)

  cookie_type  data_date    col
0    avg(0-d)   20181006     1
1    avg(e-f)   20181006     2
2    avg(e-f)   20181007     905

Answer 2

最后，我在“廖天华”的帮助下解决了这个问题：

frame1.index = frame1.data_date.astype(str) + frame1.cookie_type
next_day_dau.index = next_day_dau.data_date.astype(str) + next_day_dau.cookie_type
dau_7.index = dau_7.data_date.astype(str) + dau_7.cookie_type
dau_15.index = dau_15.data_date.astype(str) + dau_15.cookie_type
# get_index
next_day_dau_idx = frame1.index.isin(next_day_dau.index)
dau_7_idx = frame1.index.isin(dau_7.index)
dau_15_idx = frame1.index.isin(dau_15.index)
#
if any(next_day_dau_idx):
    frame1.loc[next_day_dau_idx, "next_dau"] = next_day_dau.next_dau
if any(dau_7_idx):
    frame1.loc[dau_7_idx, "dau_7"] = dau_7.dau_7
if any(dau_15_idx):
    frame1.loc[dau_15_idx, "dau_15"] = dau_15.dau_15

数据框combin_first效果不如fillna

2 个答案: