Question

我有以下实体：

@Entity
public class ApplicationUser {

    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    public long id;
    private String username;
    private String firstName;
    private String lastName;
    @Length(min = 2, max = 60)
    private String password;
    private Long tsRegistration;
    private Long tslLastLogin;
    private Long bonusCredit;
    private String nationality;
    private String battleTag;
    private Integer mmr;
    private boolean enabled;
    private boolean tokenExpired;
    private String nickname;

    @JsonIgnore
    @ManyToMany
    @JoinTable(
            name = "users_roles",
            joinColumns = @JoinColumn(
                    name = "user_id", referencedColumnName = "id"),
            inverseJoinColumns = @JoinColumn(
                    name = "role_id", referencedColumnName = "id"))
    private List<Role> roles;

和

@Entity
@Data
public class Match {

    @Id
    @GeneratedValue(strategy = GenerationType.AUTO)
    public long id;


    @LazyCollection(LazyCollectionOption.FALSE)
    @OneToMany
    public List<ApplicationUser> users;

    @JsonIgnore
    @ManyToOne
    @JoinColumn(name = "tournament_id")
    public Tournament tournament;

    public Integer qualifyingRound;

    public String winner;

    public Match(List<ApplicationUser> users, Tournament tournament, Integer qualifyingRound) {
        this.users = users;
        this.tournament = tournament;
        this.qualifyingRound = qualifyingRound;
        this.winner = null;
    }

我正在开发一种测试，试图在给定的锦标赛中为玩家生成新的比赛。比赛开始时，已经为用户生成了比赛，并且比赛例外。但是，当我与相同的用户，相同的锦标赛，但排位赛不同而产生比赛时，（因为相同的用户可能恰好必须在同一锦标赛中进行对战），我得到了

Unique index or primary key violation: "UK_9PXJMR2KVN9AQYI2A0AYB5BSC_INDEX_2 ON PUBLIC.MATCH_USERS(USERS_ID) VALUES (2, 1)"; SQL statement:
insert into match_users (match_id, users_id) values (?, ?) [23505-197]

执行以下查询后：

Hibernate: 
    insert 
    into
        match_users
        (match_id, users_id) 
    values
        (?, ?)

为什么会这样？ match_id是否应该与之前插入的ID不同？这是生成错误的测试代码：

    @Test
public void prova(){

    SwissSystemTournament tournament = (SwissSystemTournament) tournamentService.getRepository().save(new SwissSystemTournament("Test tournament", 12,
            "Hearthstone", "image/img2.jpg", "Italy", "3v3", System.currentTimeMillis(), 3));

    List<ApplicationUser> users = new ArrayList<>();

    users.add(new ApplicationUser("testuser000@gmail.com", "AliceF", "AliceL", "sdadasdaddsada",
            "Europe", "TestUser000", roleRepository.findByName("ROLE_USER"), "TestNicktestuser000"));

    users.add(new ApplicationUser("testuser001@gmail.com", "BobF", "BobL", "wqeqweqweeq",
            "Europe", "TestUser001", roleRepository.findByName("ROLE_USER"), "TestNicktestuser001"));

    tournamentService.getRepository().save(tournament);

    userService.getRepository().save(users.get(0));
    userService.getRepository().save(users.get(1));

    Match match1 =new Match(users,tournament,1);
    matchService.getRepository().save(match1).getId();

    Match match2 = new Match(users,tournament,2);
    matchService.getRepository().save(match2).getId();
}

Answer 1

正如rj-hwang所说，我必须对Match.users使用@manyToMany批注，因为这是用户和match之间的正确关系。谢谢！

唯一索引或主键冲突休眠

1 个答案: