Question

我有一个模型，该模型的属性需要映射到抽象类ClassAModel和ClassBModel与ClassA和ClassB一对一的实体

public class Model
{
    public int Number { get; set; }
    public ClassAModel ClassAModel { get; set; }
    public ClassBModel ClassBModel { get; set; }
}

public abstract class AbstractClass
{
    public int Number { get; set; }
}

public class ClassA : AbstractClass
{

}

public class ClassB : AbstractClass {

}

我不知道如何告诉自动映射器从ClassAModel属性映射ClassA

Answer 1

此答案假设您尝试使用Model中的属性和ClassA中的number属性将ClassAModel映射到Model：

CreateMap<Model, ClassA>()
    .ConstructProjectionUsing(x => new ClassA(){Name = x.ModelClassA.Name, Number = x.Number});

此答案假定您要将Model映射到ClassA和ClassB的实例。这使用了动态包装两个对象。

CreateMap<Model, dynamic>()
                .ConstructProjectionUsing(x =>  new { A = new ClassA() { Name = x.ModelClassA.Name, Number = x.Number },
                    B = new ClassB() { Department  = x.ModelClassA.Name, Number = x.Number }});

希望这些对您有所帮助。

要减少手动映射，您可以改为执行以下操作（未经测试的代码）：

CreateMap<Model, ClassA>()
    .ConstructProjectionUsing(x => Mapper.Map<ClassA>(x.ModelClassA))
    .ForMember(x => x.Number, y => y.MapFrom(src => src.Number));

CreateMap<Model, ClassB>()
    .ConstructProjectionUsing(x => Mapper.Map<ClassB>(x.ClassBModel))
    .ForMember(x => x.Number, y => y.MapFrom(src => src.Number));

CreateMap<Model, dynamic>().ConstructProjectionUsing(x => new {A = Mapper.Map<Model, ClassA>(x), B = Mapper.Map<Model, ClassB>(x)});

Automapper展平带有继承的对象

1 个答案: