Question

我有以下SOAP响应。使用我的代码，我只能提取一个元素。然后抛出空引用异常错误。

如何在C＃函数中将Item-> key和Item-> value提取到字典中？

以下是我用来从中提取数据的功能的一部分。

<?xml version="1.0" encoding="UTF-8"?>
<SOAP-ENV:Envelope xmlns:SOAP- ENV="http://schemas.xmlsoap.org/soap/envelope/" xmlns:ns1="urn:Magento" xmlns:ns2="http://xml.apache.org/xml-soap" xmlns:SOAP-ENC="http://schemas.xmlsoap.org/soap/encoding/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" SOAP-ENV:encodingStyle="http://schemas.xmlsoap.org/soap/encoding/">
<SOAP-ENV:Body>
    <ns1:callResponse>
        <callReturn SOAP-ENC:arrayType="ns2:Map[2]" xsi:type="SOAP-ENC:Array">
            <item xsi:type="ns2:Map">
                <item>
                    <key xsi:type="xsd:string">state</key>
                    <value xsi:type="xsd:string">processing</value>
                </item>
                <item>
                    <key xsi:type="xsd:string">status</key>
                    <value xsi:type="xsd:string">processing</value>
                </item>
                <item>
                    <key xsi:type="xsd:string">protect_code</key>
                    <value xsi:type="xsd:string">ba8dd7</value>
                </item>
                <item>
                    <key xsi:type="xsd:string">shipping_firstname</key>
                    <value xsi:type="xsd:string">Roshan</value>
                </item>
                <item>
                    <key xsi:type="xsd:string">billing_name</key>
                    <value xsi:type="xsd:string">Roshan India</value>
                </item>
                <item>
                    <key xsi:type="xsd:string">shipping_name</key>
                    <value xsi:type="xsd:string">Roshan India</value>
                </item>
                <item>
                    <key xsi:type="xsd:string">order_id</key>
                    <value xsi:type="xsd:string">2</value>
                </item>
            </item>
        </callReturn>
    </ns1:callResponse>
</SOAP-ENV:Body>
</SOAP-ENV:Envelope>

代码

 try
        {
            XmlDocument xdoc = new XmlDocument();//xml doc used for xml parsing
            xdoc.LoadXml(content);  // --------> THIS IS WHERE I PASS SOAP RESPONSE
            XmlNamespaceManager nsmgr = new XmlNamespaceManager(xdoc.NameTable);
            nsmgr.AddNamespace("SOAP-ENV:encodingStyle", "http://schemas.xmlsoap.org/soap/encoding/");

            XmlNodeList xNodelst = xdoc.DocumentElement.SelectNodes("//item");
            int nodes = xNodelst.Count;
            dynamic item;
            Dictionary<string, string> items = new Dictionary<string, string>();
            foreach (XmlNode xn in xNodelst)
            {
                XmlNode itemnode = xn["item"];
                if (itemnode != null) {
                    string key = itemnode["key"].InnerText;
                    string value = itemnode["value"].InnerText;
                    items.Add(key, value);
                }

            }
            var ss = items;
            return "";
        }
        catch (Exception e) {
            return e.Message;
        }

Answer 1

xml具有两个级别的标记项。因此，您必须确保分别对待item标记的每个级别。我使用xml linq来获取数据并将结果放入字典中。

TreeMap

Answer 2

我终于设法完成了这项工作。我在名称空间管理器变量中添加了所有名称空间。并使用xPath如下浏览XML，

    XmlNodeList xNodelst = xdoc.DocumentElement.SelectNodes("//item[@xsi:type]",nsmgr);

这有助于我解决问题。如果有人遇到类似问题，我会在这里发布。

干杯！

            string soapString = @"<soapenv:Envelope xmlns:xsi=""http://www.w3.org/2001/XMLSchema-instance"" xmlns:xsd=""http://www.w3.org/2001/XMLSchema"" xmlns:soapenv=""http://schemas.xmlsoap.org/soap/envelope/"" xmlns:urn=""urn:Magento""><soapenv:Header/><soapenv:Body><urn:call soapenv:encodingStyle=""http://schemas.xmlsoap.org/soap/encoding/""><sessionId xsi:type=""xsd:string"">"+ssid +@"</sessionId><resourcePath xsi:type=""xsd:string"">sales_order.list</resourcePath><args xsi:type=""xsd:anyType""></args></urn:call></soapenv:Body></soapenv:Envelope>";
            HttpResponseMessage response = await PostXmlRequest("http://localhost/M1/api.php", soapString);
            string content = await response.Content.ReadAsStringAsync();

            XmlDocument xdoc = new XmlDocument();//xml doc used for xml parsing
            xdoc.LoadXml(content);
            XmlNamespaceManager nsmgr = new XmlNamespaceManager(xdoc.NameTable);
            nsmgr.AddNamespace("ns1", "urn:Magento");
            nsmgr.AddNamespace("ns2", "http://xml.apache.org/xml-soap");
            nsmgr.AddNamespace("xsi", "http://www.w3.org/2001/XMLSchema-instance");
            nsmgr.AddNamespace("xsd", "http://www.w3.org/2001/XMLSchema");
            nsmgr.AddNamespace("SOAP-ENV", "http://schemas.xmlsoap.org/soap/envelope/");
            nsmgr.AddNamespace("encodingStyle", "http://schemas.xmlsoap.org/soap/encoding/");               

            XmlNodeList xNodelst = xdoc.DocumentElement.SelectNodes("//item[@xsi:type]",nsmgr);

            int nodes = xNodelst.Count;                
            Dictionary<int, IDictionary> items = new Dictionary<int, IDictionary>();

            int n = 0;
            foreach (XmlNode xn in xNodelst)
            {
                XmlNode itemnode = xn;
                Dictionary<string, string> itemData = new Dictionary<string, string>();
                foreach (XmlNode xn1 in itemnode)
                {
                    string key = xn1["key"].InnerText;
                    string value = xn1["value"].InnerText;
                    itemData.Add(key, value);
                }                        
                items.Add(n, itemData);
                n++;
            }
 return items;

如何在C＃中从SOAP响应中提取数据

2 个答案: